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2 years ago

An LDR was placed near a light source. The following results were

Physics

1 answer:

Zina [86]2 years ago

6 0

Answer:

V = 440I

Explanation:

According to ohm's law which states that the current passing through a metallic conductor at constant temperature is directly proportional to the potential difference across its ends.

Let V be the potential difference

I is the current

R is the resistance

Mathematically;

V∝I

V = IR

Given

Potential difference V = 5.50Volts

Current = 12.5mA = 12.5*10^-3A

Current I = 0.0125A

Recall that V = IR

R = V/I

Substitute the given parameters into the formula;

R = 5.50/0.0125

R = 440 ohms

Hence the equation that links current, potential difference and resistance is expressed as;

V = I(440)

V = 440I

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Answer:

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Explanation:

Given that,

Distance = 1.0 m

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Speed = 35 m/s

Angle = 53°

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(a). We need to calculate the induced emf

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$E = Blv\sin\theta$

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$E=5.0\times10^{-5}\times1.0\times35\sin53^{\circ}$

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$I=\dfrac{E}{R}$

Put the value into the formula

$I=\dfrac{1.398\times10^{-3}}{3.0}$

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(b). We need to calculate the power dissipated through the resistor

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$P=I^2 R$

Put the value into the formula

$P=(0.5\times10^{-3})^2\times3.0$

$P=7.5\times10^{-7}\ Watt$

Hence, The induced current and the power dissipated through the resistor are 0.5 mA and $7.5\times10^{-7}\ Watt$ .

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