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2 years ago

An LDR was placed near a light source. The following results were

Physics

1 answer:

Zina [86]2 years ago

6 0

Answer:

V = 440I

Explanation:

According to ohm's law which states that the current passing through a metallic conductor at constant temperature is directly proportional to the potential difference across its ends.

Let V be the potential difference

I is the current

R is the resistance

Mathematically;

V∝I

V = IR

Given

Potential difference V = 5.50Volts

Current = 12.5mA = 12.5*10^-3A

Current I = 0.0125A

Recall that V = IR

R = V/I

Substitute the given parameters into the formula;

R = 5.50/0.0125

R = 440 ohms

Hence the equation that links current, potential difference and resistance is expressed as;

V = I(440)

V = 440I

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Which gas giant has a rotation axis so tilted that the planet rotated like a bowling ball as it orbits the sun?

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3 years ago

Which would you use with a circuit to determine if a magnet was moving in close proximity to the circuit?

stealth61 [152]

Answer:

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The amount of energy that remains after the amount of energy used for respiration is subtracted from the total is called

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Answer:Gibb's free energy

Explanation:

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3 years ago

The intensity of an earthquake wave passing through the earth is measured to be 2.5×106 j/(m2⋅s) at a distance of 43 km from the

vampirchik [111]

r₁ = distance of the point from the source = 43 km = 43000 m

I₁ = intensity of earthquake wave at distance "r₁" = 2.5 x 10⁶ W/m²

r₂ = distance of the point from the source = 1.5 km = 1500 m

I₂ = intensity of earthquake wave at distance "r₂" = ?

we know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .

I α 1/r² where I = intensity of wave , r = distance from source

hence we can write

I₁/I₂ = r₂²/r₁²

inserting the values

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4 0

3 years ago

A playground merry-go-round has a mass of 50 kg and a diameter of 4.0 m. There are 4 children who want to ride on it. They have

mixer [17]

Answer:

B) I1 = 1680 kg.m^2 I2 = 1120 kg.m^2

C) V = 0.84m/s T = 29.92s

D) ω2 = 0.315 rad/s

Explanation:

The moment of inertia when they are standing on the edge:

$I1 = 1/2*M*R^2 + (m1+m2+m3+m4)*R^2$ where M is the mass of the merry-go-round.

I1 = 1680 kg.m^2

The moment of inertia when they are standing half way to the center:

$I2 = 1/2*M*R^2 + (m1+m2+m3+m4)*(R/2)^2$

I2 = 1120 kg.m^2

The tangencial velocity is given by:

V = ω1*R = 0.84m/s

Period of rotation:

T = 2π / ω1 = 29.92s

Assuming that there is no friction and their parents are not pushing anymore, we can use conservation of the angular momentum to calculate the new angular velocity:

I1*ω1 = I2*ω2 Solving for ω2:

ω2 = I1*ω1 / I2 = 0.315 rad/s

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3 years ago