All categories

2 years ago

Why do researchers work in teams?

Physics

2 answers:

mariarad [96]2 years ago

8 0

Because it is easier

Feliz [49]2 years ago

5 0

Researchers works in teams to divide the work up and to have different opinions and other minds combine to get work done.

You might be interested in

PLEASE HELP While the Earth is revolving around the sun, less direct sunlight is reaching the Northern Hemisphere than the South

jekas [21]

Answer:

Winter

Explanation:

Earth Rotates about an axis

7 0

2 years ago

Is the image formed by a plane mirror always real?<br><br>True or false?

mafiozo [28]

This statement is false

6 0

1 year ago

I hope everyone is ok rn with this tornado . prayers if anyone hurt

skad [1K]

<h2><em>THERE WAS A TORNADO????????????</em></h2><h2><em></em></h2><h2><em>SAY WHAT?!</em></h2>

4 0

2 years ago

Read 2 more answers

A reconnaissance plane flies 560 km away from its base at 602 m/s, then flies back to its base at 903 m/s.

IrinaVladis [17]

Answer:

Approximately $722\; \rm m\cdot s^{-1}$ .

Explanation:

The average speed of a vehicle is calculated as:

$\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}$ .

In this question, the total distance is $2 \times 560\; \rm km = 1120\; \rm km$ .

The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:

$560 \; \rm km = 560 \times 10^{3} \; \rm m = 5.6 \times 10^{5}\; \rm m$ .

$1120 \; \rm km = 1120 \times 10^{3} \; \rm m = 1.12 \times 10^{6}\; \rm m$ .

Time required for the first part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{602\; \rm m\cdot s^{-1}} \approx 930\; \rm s$ .

Time required for the second part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{903\; \rm m\cdot s^{-1}} \approx 620\; \rm s$ .

The time required for the entire trip would be approximately $930 + 620 = 1550\; \rm s$ .

Calculate the average speed of this plane:

$\begin{aligned} \text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &\approx \frac{1.12\times 10^{6}\; \rm m}{1550\; \rm s} \approx 722\; \rm m \cdot s^{-1}\end{aligned}$ .

6 0

1 year ago

One significant result of the Michelson experiment of 1880 was that it:

Alika [10]

Answer:

calculated the speed of light over a short distance

Explanation:

Albert Michelson <u>was an American physicist who conducted an experiment regarding the speed of light in the air 1880s.</u> He believed in the existence of "aether," a field of space that is deemed necessary for transporting electromagnetic forces. In order to do this, he setup a device in order to accurately measure the speed of light in in aether. His device is now known as <u>"Michelson interferometer." </u><em>The result was actually negative. </em>

In order to make his experiment even more accurate, he collaborated with Edward Morley, a famous American scientist. Although the result failed, together, they were able to improve and come with the a standard length of light. This calculated the speed of light over a short distance, which was the significant result of Michelson's experiment.

Thus, this explains the answer.

8 0

2 years ago

Read 2 more answers