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melamori03 [73]
2 years ago
11

Suppose you have a 75-watt light bulb that you leave turned on for two minutes. How much energy

Physics
1 answer:
victus00 [196]2 years ago
5 0

Answer:

9000 J

Explanation:

Convert minutes to seconds.

2 min = 120 s

Power = energy / time

75 W = E / 120 s

E = 9000 J

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How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away
ELEN [110]

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

  • force = 50N
  • Distance = 1km = 1000m

Work = 50 * 1000

Work = 50,000 J

8 0
2 years ago
Find the momentum of a 25 kg remote
telo118 [61]

Answer:

100

Explanation:

Momentum (P) = Mass (M) × Velocity (V)

Momentum = 25kg × 4.0m/s

Momentum = 100kg m/s

7 0
2 years ago
Which of the following describes a closed conducting loop through which an electrical current can flow?
Romashka-Z-Leto [24]
I think the correct answer is the second option. A circuit describes a closed conducting loop through which an electrical current can flow. It is a path that an electrical current could flow. A circuit could be a closed one or an open circuit. A closed circuit would be a circuit where the current could flow continuously. An open circuit would be a type of circuit where the flow current would only go once and stopped at a particular point since the current has nowhere to go. For a circuit to work, an electric supply should be available to supply the electric current.
4 0
3 years ago
Need help anybody thanks
mars1129 [50]
If there are no windows, then the illumination in the room depends
only on the room and what's in it, not on anything outside. 
The time of day has no effect.  The other things all do. 
4 0
3 years ago
Can someone help me ?
hammer [34]

Answer:

1)    Time interval                 Blue Car                      Red Car

          0 - 2 s                Constant Velocity           Increasing Velocity

          2 - 3 s                Constant Velocity           Constant Velocity

          3 - 5 s                Constant Velocity           Increasing Velocity

          5 - 6 s                Constant Velocity           Decreasing Velocity

2) For Red and Blue car y₂  = 120       v = \frac{y_{2}-y_{1}}{t_{2}-t_{1}} = \frac{120-0}{6-0} = 20 m/s

     We get the same velocity for two cars because it is the average velocity of the car at the given interval of time. It is measured for initial and final position.

3)   At t = 2s, the cars are the same position, and are moving at the same rate

                    Position - same

                    Velocity - same

The position-time graph shares the same spot for two cars.

4 0
3 years ago
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