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3 years ago

Are al mixtures solutions?

Physics

1 answer:

zmey [24]3 years ago

3 0

Not all mixtures are solutions. All solutions are mixtures because it is two or more substances mixed together.

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The radio signal sent from the Earth to the Moon was received again on Earth 2.6 seconds after it was sent. The signal ran at 30

Pavlova-9 [17]

Answer:

390000 km

Explanation:

2.6 / 2 = 1.3 (second)

300000 * 1.3 = 390000 km

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3 years ago

Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m/s^2, where t is in seconds. What

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To solve this problem we will use the given expression and derive it in order to find the algebraic expressions of velocity and position. These equations will be similar to those already known in the cinematic movement but will be subject to the previously given function. We start deriving the equation for velocity

$a = 2t-6$

$\frac{dv}{dt} = 2t-6$

Integrate acceleration equation

$\int dv = (2t-6)dt$

$v = 2(\frac{t^2}{2})-6t+C_1$

$v=t^2-6t+C_1$

At $t = 0, v = 0$

Replacing,

$0 = 0^2-6*0+C_1$

Therefore the value of the first Constant is

$C_1 = 0$

The expression can be escribed as,

$v = t^2-6t$

Calculate the velocity after 6s,

$v=t^2-6t$

$v = 6^2-6*6$

$v = 0m/s$

Now using the same expression we can derive the equation for distance

$v = t^2-6t$

$\frac{dx}{dt} =t^2-6t$

$\int dx = \int (t^2-6t)dt$

$x = \frac{t^3}{3}-6\frac{t^2}{2}+C_2$

At t=0, x=0

$0 = \frac{0^3}{3}-6(\frac{0^2}{2})+C_2$

Therefore the value of the second constant is

$C_2 = 0$

$x = \frac{t^3}{3}-\frac{6t^2}{2}$

Calculate the distance traveled after 11 s

At $t=11s$

$x = \frac{11^3}{3}-6(\frac{11^2}{2})$

$x = 80.667m$

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3 years ago

True or false An example of a destructive force is the formation of mountains.

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Answer:

i would say it is true

hope i helped

Explanation:

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C. is your answer! Hope it helps!

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You are shooting at a moving target. you estimate the length of lead necessary to hit the target. you maintain that lead as you

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The answer to this problem is:

This method of shooting is called <u>“sustained lead”.</u>

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