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kirill115 [55]
3 years ago
8

Some land plants have evolved specialized vascular tissues that have allowed them to thrive on land. The developement of these s

tructures was necessary because
Land plants need to extract water from the ground and move it to the other structures of the plant.
Land plants need to be tall and the vascular tissues are what provide rigidity to the plant’s cells.
Land plants need to photosynthesize and the vascular tissues is where this process occurs.
Land plants don’t really need these structures as they can absorb water from the air through their leaves.
Chemistry
1 answer:
jarptica [38.1K]3 years ago
7 0
<span>Plants are multicellular organisms that have evolved the ability to live on land. ... resemble the earliest land plants (bryophytes) in a variety of ways, including the structure ... These possessspecialized vascular tissues— phloem and xylem —to ... However, they are not restricted to thesehabitats, and some mosses thrive in ...</span><span>
</span>
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I think its tetrahedra or octahedra

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A layer of sandstone is found on top of a layer of shale. What most likely happened in this area?
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Mud was deposited first, then sand.

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In acidic solution, the breakdown of sucrose into glucose and fructose has this rate law: Rate = k[H⁺][sucrose]. The initial rat
yKpoI14uk [10]

In an acidic solution, the rate change if Sucrose is changed to 2.5 M will be  Rate = k[H⁺][2.51M] as the initial rate of sucrose breakdown is measured in a solution that is 0.01 M H⁺.

<h3>What is the breakdown of sucrose?</h3>

Sucrose is a type of sugar that is made by adding fructose and glucose or the breakdown of fructose will be in the form of glucose and fructose always at different levels of concentration.

In the given acidic solution if the concentration of sucrose changes from 0.01 to 2.5 then both have to add to give the total rate of change in the given reaction and it will be 2.51 M.

Therefore, Rate = k[H⁺][2.51M] as the initial rate of sucrose breakdown is measured in a solution that is 0.01 M H⁺for an acidic solution, the rate change if Sucrose is changed to 2.5 M.

Learn more about the breakdown of sucrose, here:

brainly.com/question/28297399

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6 0
2 years ago
What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2
Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0
3 years ago
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