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4 years ago

What object has the least amount of atoms

Chemistry

1 answer:

Anni [7]4 years ago

5 0

Answer:

neutron stars are made out of neutrons, so there's definitely no atoms there. The sparse matter which is between stars or between galaxies, which is the majority of the mass in the universe

Explanation:

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The number of particles in one mole of a chemical substances is 602,200,000,000,000,000,000,000 particles. What is the correct w

crimeas [40]

The correct way to write this number in scientific notation : 6.022 x 10²³

<h3>Further explanation </h3>

Scientific Notation is a standard form of writing numbers used in mathematical operations

The rules:

1. Writing order : first digit, decimal point, next digit

2. Then followed by powers of 10 (the value can be +/-)

If the value is> 10 (the power of 10 is +), the decimal point is moved to the left, to the right of the first digit

If the value is <10 ((the power of 10 is -), the decimal point is moved to the right, to the right of the first digit

I certainly didn't count the details of the number of zeros listed, but only saw the answer choices.

And the right ones are: 6.022 x 10²³

3 0

4 years ago

Read 2 more answers

Evaporate minerals, or "salts," include halite, anhydrite, and ______.

pav-90 [236]

B is the correct answer! I learned this in class last week :)

5 0

4 years ago

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Calcium carbonate is also known as limestone. It is made up of the elements _______.

tia_tia [17]

Calcium=Ca2+
Carbonate=(CO3)2-

Therefore it is composed of Calcium, Carbon and Oxygen.

6 0

3 years ago

A compound is made up of 28 g N, 24 g C, 48 g O, and 8 g H .What is the empirical formula?

vovikov84 [41]

Answer:

$\rm C_2H_8N_2O_3$ .

Explanation:

<h3>Step One: calculate the coefficients. </h3>

Look up the relative atomic mass of these four elements on a modern periodic table:

$\rm C$ : approximately $12$ .
$\rm H$ : approximately $1$ .
$\rm N$ : approximately $14$ .
$\rm O$ : approximately $16$ .

The relative atomic mass of an element is numerically equal to the mass (in grams, $\rm g$ ,) of one mole of atoms of this element.

For example, the relative atomic mass of $\rm C$ is approximately $12$ . Therefore, each mole of $\rm C\!$ atoms would have a mass of $12\; \rm g$ .

This sample contains $24\; \rm g$ of carbon. That would correspond to approximately $\displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol$ of $\rm C$ atoms.

Similarly, for the other three elements:

$\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol$ .

$\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol$ .

$\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol$ .

Hence, the ratio between these elements in this compound would be:

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ .

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ is indeed the smallest possible integer ratio between the number of atoms of these elements.

<h3>Step Two: arrange the elements in an appropriate order</h3>

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, $\rm C$ , is present in this compound, then:

$\rm C$ (carbon) and then $\rm H$ (hydrogen) will be the first two elements listed in the formula (ignore the hydrogen if it is not in the compound.)
The other elements in this compound will be listed in alphabetical order.

If there is no carbon $\rm C$ in this compound, then list all the elements in this compound in alphabetical order.

Both $\rm C$ (carbon) and $\rm H$ (hydrogen) are found in this compound. Therefore, the first element in the list would be $\rm C\!$ . The second would be $\rm H\!$ , followed by $\rm N\!$ and then $\rm O\!$ .