Answer:
C-BY LOSING ONE OR MORE ELECTRONS
Answer:
"Kinetic energy of the gas is more as compared to that of the liquids. But when compare it to the solid, kinetic energy of liquid is more."
Explanation:
a) Relatively high density : This happens as a result of the tight or packed or can be say close arrangement of the particles.
b) Ability to diffuse : As we know that in gases the constant and the random motion of the particles of the liquid leads to diffusion. But it is very slow as compared to the gases and also porque liquid particles are close together.
c) Ability to evaporate:This happens as a result of the molecules of the liquid having different kinetic energies with particles having higher than that of the average energies that move faster.
Answer:
The change in entropy of the surrounding is -146.11 J/K.
Explanation:
Enthalpy of formation of iodine gas = 
Enthalpy of formation of chlorine gas = 
Enthalpy of formation of ICl gas = 
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28ICl%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H_f_%7B%28I_2%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H_f_%7B%28Cl_2%29%7D%29%5D)
![=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol](https://tex.z-dn.net/?f=%3D%5B2%5Ctimes%2017.78%20kJ%2Fmol%5D-%5B1%5Ctimes%200%20kJ%2Fmol%2B1%5Ctimes%2062.436%20kJ%2Fmol%5D%3D-26.878%20kJ%2Fmol)
Enthaply change when 1.62 moles of iodine gas recast:

Entropy of the surrounding = 

1 kJ = 1000 J
The change in entropy of the surrounding is -146.11 J/K.
I think false is the answer .if wrong correct meeee
Correct Answer: Option g: <span>adding salt to water lowers its freezing point
Reason:
Freezing point is a colligative property. When a non-volatile solution is present in solution, it's freezing point decreases. This is referred as depression in freezing point (</span>ΔTf<span>). Extent of lowering in freezing point is dependent on number of particles present in system. Mathematically it is expressed as:
</span>ΔTf = Kf X m
<span>
where, m = molality of solution
Kf = cryoscopic constant.
Hence, a</span><span>dding salt to water lowers the freezing point of solution.</span>