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soldier1979 [14.2K]
3 years ago
15

50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter

nal energy of the system? A) The internal energy of the system would decrease by 21 J. B) The internal energy of the system would increase by 21 J. C) The internal energy of the system would decrease by 79 J. D) The internal energy of the system would increase by 79 J.
Chemistry
1 answer:
Harman [31]3 years ago
4 0

Work done=50J

Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

Hence the internal energy would increase by 21J

Option B s correct

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682mL

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Given parameters:

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Final volume = ?

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T₁ is the initial temperature  of air

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T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

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