The electric field is zero at x = -16.45cm
Data;
- q1 = 3.4 μC
- q2 = -2.0 μC
- distance = 5cm
<h3>The Electric Field at point 0</h3>
As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.
Let the point be at x.
For an electric field to be equal to zero;

Let's solve for x using mathematical methods.

Solving the above quadratic equation;

The electric field is zero at x = -16.45cm
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The forms of kinetic energy are motion, heat, sound and light.
So according to your options, I choose D) Sound energy.
That taxi will traveled 1500s by carrying the passenger.
Given: Mass of Mars Mm = 6.24 x 10²³ Kg;
Mass of Phobos Mp = 9.2 x 10¹⁵ Kg
Gravitational Force F = 4.47 X 10¹⁵ N
Gravitational constant G = 6.67 X 10⁻¹¹ N m²/Kg²
Radius r = ?
Formula: F = GMmMp/r² derive r
r = √GMmMp/F
r = √(6.67 x 10⁻¹¹ N m²/Kg²)(6.24 x 10²³ Kg)(9.2 x 10¹⁵ Kg)/4.47 x 10¹⁵ N
r = √(6.67 x 10⁻¹¹ N m²/Kg²)5.74 x 10³⁹ Kg²/4.47 x 10¹⁵ N
r = √8.57 x 10¹³ m
r = 9,257,429 m
or r = 9.26 x 10⁶ m
Because air does not exist in space