V = d ÷ t --> bc d=vt
V = (76+54)÷(2+5) = 130÷7 = 18.57km/hr
One that can help you is:
ΔT=<span>T<span>Final</span></span>−<span>T<span>Initia<span>l
That is of course adding both tmepratures. There is one more that is a lil bit more complex
</span></span></span><span><span>Tf</span>=<span>Ti</span>−Δ<span>H<span>rxn</span></span>∗<span>n<span>rxn</span></span>/(<span>C<span>p,water</span></span>∗<span>m<span>water</span></span>)
This one is taking into account that yu can find temperature and that there could be a change with a chemical reaction. Hope this helps</span>
The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g
<h3>
What is Mass and Weight ?</h3>
Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.
What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?
The total mass will be the sum of the three masses.
The total mass = 117 + 19.43 + 6.1043
The total mass = 142.5343 g
Convert gram to kilogram by dividing the answer by 1000
The total mass = 142.5343/1000
The total mass = 0.1425343 Kg
Therefore, the value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g approximately
Learn more about Mass and Weight here: brainly.com/question/1384116
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Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
If they have the same momentum, then
m₁ v₁ = m₂ v₂
If m₁ > m₂, then we must have v₁ < v₂ to preserve the equality.
The object with the larger speed - the second object - thus has more kinetic energy.
