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anastassius [24]
3 years ago
12

He output voltage and current of a transformer are determined by the

Physics
2 answers:
neonofarm [45]3 years ago
4 0
The output voltage of a transformer is

                           (input voltage) x (number of turns of wire in secondary) 
           divided by
                          (number of turns of wire in the primary winding) .


The output current is

                           (output voltage)
             divided by
                           (total resistance in the circuit connected to the output).
Ede4ka [16]3 years ago
3 0

Answer: the number of turns in the primary and secondary coils

Explanation:

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Question 2 of 25
True [87]

Answer: The symbol representing  the result of a  gas expanding against a constant pressure is W

Explanation:

According to first law of thermodynamics, energy can neither be destroyed nor created but rather transferred to one place to another and converted to and from other energy forms.

The mathematical form of first law of thermodynamics is:

\Delta U=q+W

where \Delta U = change in internal energy

q = heat absorbed or released

W = work  (W= P\Delta V)

P = pressure

\Delta V = volume change

Thus the changes in heat or work leads to change in internal energy.

5 0
3 years ago
Is an electron an antiparticle, boson, lepton, or hadron?
Masteriza [31]

Answer:

An electron is a lepton

4 0
3 years ago
The rhinestones in costume jewelry are glass with index of refraction 1.50. To make them more reflective, they are often coated
Sedaia [141]

Answer:

60

Explanation:

According to the given question, the computation of minimum coating thickness is shown below:-

The condition for constructive interference is

2t_{min} = (m + \frac{1}{2} )\times \frac{\lambda}{^nmateral}

= (0 + \frac{1}{2} )\times \frac{\lambda}{^nmateral}

t = \frac{\lambda}{4n}

Now we will put the values to the above formula to reach the answer

= \frac{480nm}{4\times 2.0}

= 60

Therefore we simply applied the above formula to determine the minimum coating thickness

6 0
3 years ago
What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?
skad [1K]

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

8 0
3 years ago
A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

8 0
3 years ago
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