Answer:
The constant angular acceleration of the centrifuge = -252.84 rad/s²
Explanation:
We will be using the equations of motion for this calculation.
Although, the parameters of this equation of motion will be composed of the angular form of the normal parameters.
First of, we write the given parameters.
w₀ = initial angular velocity = 2πf₀
f₀ = 3650 rev/min = (3650/60) rev/s = 60.83 rev/s
w₀ = 2πf₀ = 2π × 60.83 = 382.38 rad/s
θ = 46 revs = 46 × 2π = 289.14 rad
w = final angular velocity = 0 rad/s (since the centrifuge come rest at the end)
α = ?
Just like v² = u² + 2ay
w² = w₀² + 2αθ
0 = 382.38² + [2α × (289.14)]
578.29α = -146,214.4644
α = (-146,214.4644/578.29)
α = - 252.84 rad/s²
Hope this Helps!!!
Answer:
Tangential
Explanation: This is a kind of force which act on a moving body in such a way that it is curved in the direction of the path of the body. This implies that when the velocity of the object is positive, the acceleration will be negative.
Answer:
2.6h
Explanation:
I attached the image below of the work hope you can see it. Hope this helps!
The broom handle that she have to balance if she hung a 400g mass from the end of the broom handle is 5.24m
This problem is centered on moment. Moment is the turning effect of a force about a point. It is expressed as:
Moment = Force× Distance
According to principle of moment, the sum of clockwise moment is equal to sum of anticlockwise moment at shown
M1d1 = M2d2
Given the following
M1 = 1.5kg
d1 = 1.4m
M2 = 400g = 0.4kg
d2 is required
Substitute
1.5(1.4) = 0.4d2
2.1 = 0.4d2
d2 = 2.1/0.4
d2 = 5.24m
Hence the broom handle that she have to if she hung a 400g mass from the end of the broom handle is 5.24m
Learn more here: brainly.com/question/21945515
Let
be the average acceleration over the first 2.46 seconds, and
the average acceleration over the next 6.79 seconds.
At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let
be the velocity of the car after the first 2.46 seconds.
By definition of average acceleration, we have


and we're also told that

(or possibly the other way around; I'll consider that case later). We can solve for
in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:


Now we can solve for
. We find that

In the case that the ratio of accelerations is actually

we would instead have

in which case we would get a velocity of
