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Vikentia [17]
2 years ago
9

Food and electricity are the examples of_________________​

Physics
2 answers:
mash [69]2 years ago
4 0

Answer:

sources of energy

lisov135 [29]2 years ago
4 0

Answer:

energy

Explanation:

hope this is the right answer

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Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.57 A out of the jun
AlekseyPX

Answer:

a. 1.56 × 10¹⁸ electrons per second

b. The electrons in wire 3 flow into the junction.

Explanation:

Here is the complete question

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire 3? (b) In which direction do the electrons move in wire 3 -- into or out of the junction?

Solution

(a) How many electrons per second move past a point in wire 3?

Using Kirchhoff's current law, at the junction, i₁ + i₂ + i₃ = 0 where i₁ = current in wire 1 = 0.40 A, i₂ = current in wire 2 = 0.65 A and  i₃ = = current in wire 3,

So, i₃ = -(i₁ + i₂)

taking current flowing into the junction as positive and those leaving as negative, i₁ = + 0.40 A and i₂ = -0.65 A

So, i₃ = -(i₁ + i₂)

i₃ = -(0.40 A + (-0.65 A))

i₃ = -(0.40 A - 0.65 A)

i₃ = -(-0.25 A)

i₃ = 0.25 A

Since i₃ = 0.25 C/s and we have e = 1.602 × 10⁻¹⁹ C per electron, then the number of electrons flowing in wire 3 per second is i₃/e = 0.25 C/s ÷ 1.602 × 10⁻¹⁹ C per electron = 0.1561  × 10¹⁹ electrons per second = 1.561  × 10¹⁸ electrons per second ≅ 1.56 × 10¹⁸ electrons per second

(b) In which direction do the electrons move -- into or out of the junction?

Given that i₃ = + 0.25 A and that positive flows into the junction, thus, the electrons in wire 3 flow into the junction.

8 0
3 years ago
A projectile is fired with a velocity of 45 m/s at an angle of 32°. What is the
Dennis_Churaev [7]

Answer:

C

Explanation:

To calculate adjacent of triangle use

\cos(32)  =  \frac{a}{45}

where 45 is the hypotenuse, and a is the adjacent side (horizontal component)

45 \cos(32)  = 38.16

then round to 38.2

8 0
3 years ago
How does gay-lussac's law apply to everyday life?
vladimir2022 [97]
Gay-Lussac's Law shows the direct relationship between pressure and temperature for an ideal gas with constant volume. Mathematically it is
\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} 

This particular has a lot of application in our everyday life. In cooking, for example, we apply this concept when using a pressure cooker. We increase/decrease the temperature to meet the right amount of pressure.
 
In addition, knowing that pressure increases when temperature does can help you with road safety. Knowing that temperature affects heat directly, we must be careful in making sure that tires are not overheated or else they explode out of too much pressure inside.



5 0
3 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
Oksanka [162]

Answer:

Explanation:

The momentum of the first piece = m v =- m x 31 i kg m/s in - x direction  direction

The momentum of the second piece = -m x 31 j kg m /s in Y - direction

Total momentum = - 31 m( i + j )

To conserve momentum , the third piece must have momentum equal to this

and opposite to it

So momentum of the third piece  = 3m x V = 31 m ( i +j )

V = 31/3 ( i + j ) =

Magnitude of velocity V = √2 x 31/ 3  = 14.6 m / s

Its direction will be towards the vector i + j  ie 45° from x - axis in positive direction

4 0
3 years ago
Speed (mph) 58 72 55 65 70 81 66 What car goes the fastest? Put the car speed in order, from fastest to slowest miles per hour.
RoseWind [281]

Answer:

The answer to your question is letter B

Explanation:

Data

Order from fastest to slowest speed

           58 72 55 65 70 81 66

The fastest is  81, then, 72, 70, then, 66, 65 finally 58 and 55

The correct order

       81 mi/h, 72 mi/h, 70 mi/h, 66 mi/h, 65 mi/h, 58 mi/h, 55 mi/h

The other options are from slowest to fastest or a different order.

7 0
3 years ago
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