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4 years ago

Identify the situations that have an unbalanced force. Check all that apply.

Physics

2 answers:

pochemuha4 years ago

7 0

the answer is.......................1,4,5

faltersainse [42]4 years ago

5 0

Answer:

A weight speeds up as it falls through the air.

A bumper car hit by another car moves off at an angle.

A balloon flies across the room when the air is released.

Explanation:

An object accelerates when unbalanced force acts on it that is some net non zero force acts on it.

With balanced force, i.e. the net zero force, the object is at rest or moves in straight line at constant speed.

The given situations that have an unbalanced force acting on it are:

A weight speeds up as it falls through the air - the weight accelerates as it falls towards ground.

A bumper car hit by another car moves off at an angle- the cars collide, unbalanced force causes the direction of the car to change

A balloon flies across the room when the air is released - when air is released, an equal of force acts on the balloon in opposite direction and thus it flies.

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A ball moving 2 ft/s rolls off a table (on earth) that is 32 inches high. How long will it take the ball to hit the floor answer

mart [117]

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3 years ago

A 0.150-kg cart that is attached to an ideal spring with a force constant (spring constant) of 3.58 N/m undergoes simple harmoni

SVETLANKA909090 [29]

Answer:

E = 0.01 J

Explanation:

Given that,

The mass of the cart, m = 0.15 kg

The force constant of the spring, k = 3.58 N/m

The amplitude of the oscillations, A = 7.5 cm = 0.075 m

We need to find the total mechanical energy of the system. It can be given by the formula as follows :

$E=\dfrac{1}{2}kA^2$

Put all the values,

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3 years ago

Two loudspeakers, 4.5 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them

irga5000 [103]

Answer:

A) Frequency of Sound B = 242.85 Hz

B) Frequency at maximum sound intensity = 485.71 Hz

Explanation:

From intensity and path difference equations of sound waves;

the path difference for maximum intensity is x = nλ

Now, for minimum intensity, the path difference(x) is given as;

x = (2n - 1)(λ/2)

Since he has moved 0.35m,the total Path difference = (0.35) + (0.35) = 0.7 m

As n = 1,

0.7 = =(2(1) - 1)(λ/2)

So, (λ/2) = 0.7

And thus λ = 0.7 x 2 = 1.4m

From wavelength equation, we know that; λ = v/f and f = v/λ

Where v is velocity of sound

Thus ; frequency(min) = 340/1.4= 242.85 Hz

B) Now for max the path difference;

From earlier said, x = nλ

So at n=1 and λ = 0.7

x = 1 x 0.7 = 0.7

So following same equation for frequency, fmax = 340/0.7 = 485.71 Hz

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