For the time being, let us assume that the Earth is spherical and its density depends on the radial distance from its centre. The magnitude of the gravitational force acting on the particle with mass m, located on the surface of the Earth r from Earth's center can written as
F = GMem/r^2...... 1 . where, Me = mass of the Earth, G = Universal grvitational constant.
From Newton's second law, this F can be written as
F = mg ....... 2 . where g = acceleration due to gravity
Equating 1 and 2 you get,
g = GMe/r^2.... 3
m and m will cancel out each other.
3 says that, *no matter what the mass of an object is, its acceleration under free fall gravity will always be g if and only if object is dropped near the surface of the Earth*
Radius of planet X is thrice the radius of Earth.
Plug R = 3R in equation 3 and let Mx be the mass of planet X, you will get,
g = GMx/9R.......... 4
I wrote about g for planet X because it's been given that her weight is same on both the planets.
Now divide 3 and 4 to get relation between Mx and Me (:
Answer: The mean of the samples is 32.325.
Proportion of the defective unit is =
Explanation:
The point estimate of the mean of the sample:
First calculate the mean of the 40 samples:
The mean of the samples is 32.325.
Defected pieces in the samples whose life span is less than the 26 days = 2
Proportion of the defective unit is =
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that the friction force on two boxes is given as
Now we know by Newton's II law
so we have
Part b)
For block B we know that net force on it will push it forward with same acceleration so we have
Part c)
If Alex push from other side then also the acceleration will be same
So for box B we can say that Net force is given as