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Alexandra [31]
3 years ago
10

In scientific notation, (6.2 x 10^4) x (3.3 x 10^2 ) equals ____________________.

Physics
2 answers:
gregori [183]3 years ago
8 0

For this case we have the following multiplication:

(6.2 * 10 ^ 4) * (3.3 * 10 ^ 2)

For associative property, we can rewrite the expression as:

(6.2 * 3.3) * (10 ^ 4 * 10 ^ 2)

Then, by properties of exponents we have:

In the multiplication, if we have the same base, the exponents are added.

Therefore, by rewriting the expression we have:

(6.2 * 3.3) * (10 ^{4 + 2})

Finally:

(20.46) * (10 ^ 6)

Then, we rewrite the result correctly in scientific notation.

To do this, we move the point one space to the left and increase the degree of the exponent one unit:

2.046 * 10 ^ 7

Answer:

In scientific notation, (6.2 * 10 ^ 4) * (3.3 * 10 ^ 2) equals2.046 * 10 ^ 7

castortr0y [4]3 years ago
5 0
You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.
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Answer:

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A beam of light traveling through a liquid (of index of refraction n1 = 1.47) is incident on a surface at an angle of θ1 = 59° w
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Answer:

(a) n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}

(b) n_{2} = 1.349

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Refractive index of medium 1, n_{1} = 1.47

Angle of refraction for medium 1, \theta_{1} = 59^{\circ}

Angle of refraction for medium 2, \theta_{1} = 69^{\circ}

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(a) The expression for the refractive index of medium 2 is given by using Snell's law:

n_{1}sin\theta_{1} = n_{2}sin\theta_{2}

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Now,

n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}

(b) The refractive index of medium 2 can be calculated by using the expression in part (a) as:

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Refractive\ index,\ n = \frac{Speed\ of\ light\ in vacuum,\ c}{Speed\ of\ light\ in\ medium,\ v}

Thus for medium 1

n_{1} = \frac{c}{v_{1}

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(d) To calculate the velocity of light in medium 2:

For medium 2:

n_{2} = \frac{c}{v_{2}

v_{2} = \frac{c}{n_{1} = \frac{3\times 10^{8}}{1.349} = 2.22\times 10^{8}\ m/s

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