An airplane capable of an airspeed of 100 km/hr is 60 km off the coast above the sea. If the wind is blowing from the coast out
1 answer:
To solve this problem we will apply the concepts related to relative speed. We will obtain it from the deduction made on the aircraft as a speed of the two components that act on it. Through the kinematic equations of motion, we can then calculate the time required.
The airspeed of airplane is 100km/h while the wind is blowing from the coast out to sea at 40km/h. Wind is blowing from the coast out to sea means that it opposes the airspeed. Therefore, resultant relative speed of airplane is
Total distance is 60km then with this net velocity we have that the required time is
Where,
x = Displacement
t = Time
v = Velocity
Replacing,
Therefore the time taken by the plane to reach the shore is 60 minutes
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Answer:
-0.0047 rad/s²
335.103 seconds
99.18 seconds
Explanation:
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= Initial angular velocity = 1.5 ra/s
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= Angle of rotation = 40 rev
t = Time taken
Equation of rotational motion
Acceleration while slowing down is -0.0047 rad/s²
Time taken to slow down is 335.103 seconds
Solving the equation
The time required for it to complete the first 20 is 99.18 seconds as 539.11>335.103