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julia-pushkina [17]
2 years ago
15

An airplane capable of an airspeed of 100 km/hr is 60 km off the coast above the sea. If the wind is blowing from the coast out

to sea at 40 km/hr, what is the least amount of time it will take for the plane to get to shore ?
Physics
1 answer:
Nady [450]2 years ago
6 0

To solve this problem we will apply the concepts related to relative speed. We will obtain it from the deduction made on the aircraft as a speed of the two components that act on it. Through the kinematic equations of motion, we can then calculate the time required.

The airspeed of airplane is 100km/h  while the wind is blowing from the coast out to sea at 40km/h. Wind is blowing from the coast out to sea means that it opposes the airspeed. Therefore, resultant relative speed of airplane is

v_r = 100-40=60km/h

Total distance is 60km then with this net velocity we have that the required time is

v = \frac{x}{t} \rightarrow t = \frac{x}{v}

Where,

x = Displacement

t = Time

v = Velocity

Replacing,

t = \frac{60km}{60km/h} = 1hour

t = 60 minutes

Therefore the time taken by the plane to reach the shore is 60 minutes

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Answer:

a )  4.5 N.s

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velocity of the bullet(v)  = 750 m/s

a) momentum of bullet = m × v

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m × u + M × U = m × v + M × V

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V = \dfrac{4.5}{0.9}

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