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Rufina [12.5K]
3 years ago
13

Please fill this formula​

Chemistry
1 answer:
Maurinko [17]3 years ago
3 0
1.) Na
2.) Cl ( at the second blank)
sodium metal+hydrochloric acid
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When 2.3 × 10^3 g of CaCO3 are heated, the actual yield of CaO is 1.09 × 10^3g. What is
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<h3>Further explanation</h3>

Reaction

CaCO₃ ⇄ CaO+CO₂

mass CaCO₃ = 2.3 × 10³ g

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\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98

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\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%

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