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3 years ago

One yard is approximately 0.91 meter. Write a direct variation equation that relates x yards to y meters.

2 answers:

4 0

Y = kx is the direct variation equation with k being the "constant of variation"
The constant here being the conversion decimal .91
y = 0.91x

STatiana [176]3 years ago

3 0

Answer:

The Direct variation says that:

$y \propto x$

then; the equation is in the form of y =kx where k is the constant of variation.

As per the statement:

One yard is approximately 0.91 meter.

⇒1 yard = 0.91 m

by definition of proportion:

$\frac{x}{y} = \frac{1}{0.91}$

By Cross multiply we get;

$0.91x = y$

Therefore, the direct variation equation that relates x yards to y meters is: y=0.91x

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Mark and Suzie are using a bucket to empty their flooded basement. Each bucket holds five cubic feet of water and it takes 112 f

I am Lyosha [343]

Answer:

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Step-by-step explanation:

5 feet times 112 full buckets equals 560 divided by 14 times 20

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3 years ago

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Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

We kindly invite to check this question on midpoints: brainly.com/question/4747771

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2 years ago

Find the mean, range, and interquartile range of the heights of plants given

Artist 52 [7]

Answer:

Mean = 30.9

Range = 80

Interquartile Range = 36

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms. In other words that means 2, 22, 4, 36, 82, 44, 65, 30, 8, 16 go over a fraction like this. There are 10 numbers here so this is our denominator.

$\frac{2+ 22 + 4 + 36 + 82 + 44 + 65 + 30 + 8 + 16}{10}$