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3 years ago

Find the product of (k – 9)2 using the perfect square trinomial rule shown on the left.

2 answers:

8 0

2k - 18 is the answer. Whenever there's something (I.e. A number or variable) attached to a parenthesis, it means you need to multiply everything inside that parentheses to get the product

laiz [17]3 years ago

5 0

(k-9)²
=(k-9)(k-9)
=k(k)-9(k)-9(k)-9(-9)
=k²-9k-9k+81
=k²-18k+81. As a result, the product of (k – 9)2 using the perfect square trinomial rule shown on the left is k²-18k+81. Hope it help!

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there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth grade

Darya [45]

Hope this helps!

28 - 13 = 15
15 x 12 = 180 Fifth graders

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3 years ago

33 POINTS HELP ME FAST ILL MARK BRAINLIEST Henry wants to laminate the tabletop in his study room. The tabletop is the shape of

mario62 [17]

Find the area of trapezoid.

1/2(6+10)(3) = 24

Now multiply 24 by $4 to find the total cost.

24 * 4 = 96

So the total cost is $96

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3 years ago

Which of the following is a point slope equation of the line below (10,5)(2,2)

salantis [7]

Point slope form follows the equation y-y₁=m(x-x₁), so we want it to look like that. Starting off with m, or the slope, we can find this using your two points with the formula $\frac{ y_{1} -y_{2} }{ x_{1} - x_{2} }$ . Note that y₁ and x₁ are from the same point, but it does not matter which point you designate to be point 1 and point 2. Thus, we can plug our numbers in - the x value comes first in the equation, and the y value comes second, so we have
$\frac{5-2}{10-2} = \frac{3}{5}$ as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m, and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be $y- 5= \frac{3}{5} (x-10)$

Feel free to ask further questions!

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3 years ago

A group of learners is trying to identify the vertices of the feasible region from the graph shown below during a Live Classroom

wel

Answer:

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3 years ago

Line segment YV of rectangle YVWX measures 24 units.

oksian1 [2.3K]

Answer: $YX=13.85\ units$

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

$WV=YX\\\\YV=XW=24$

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You can identify that:

$\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24$

Therefore, in order to find the length of the segment YX, you must substitute values into $tan\alpha =\frac{opposite}{adjacent}$ and then you must solve for YX.

You get that this is:

$tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85$

7 0

3 years ago

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