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Katen [24]
3 years ago
9

What to do if the patient stops breaching during Fainting ?​

Physics
2 answers:
Naddika [18.5K]3 years ago
6 0
If they're not breathing, have someone call 911 or your local emergency services immediately and prepare to begin CPR. If they're breathing, position the person on their back. Raise their legs at least 12 inches above the ground.
oksian1 [2.3K]3 years ago
4 0

Answer:

unloosen the tight attire parts,open all windows for better air circulation,if he/she does not react place your hands on the chest and press gently three times per interval while giving them air through the mouth CPR then when they react place them to lie horizontal face sideways

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What is the electric field strength 7.50 x 10E-1 meters from a 2.8 x 10 E-3 C charged object?
Nadusha1986 [10]

Answer:hi

Explanation:

5 0
3 years ago
The distance between a Point on one wave and the same point on the next cycle of the wave
Gala2k [10]

Answer:

wavelength

Explanation:

the definition of wavelength is the distance between two consecutive waves. with that being said, the point from the crest of one wave to the crest of another would be wave length

8 0
2 years ago
Which answer is not a problem associated with sulfur dioxide? A) damage to buildings B) ozone depletion C) vegetation death D) b
swat32

Answer:

Answer is A. damage to buildings.

Explanation:

I hope it's helpful!

8 0
2 years ago
BRAINLIEST AND 5 STARS. HELP ASAP.
liberstina [14]
Wavelength = wavespeed / frequency

0.5 meter = speed / 200 Hz
speed = 0.5m * 200 Hz
= 100 m/s
Solved
4 0
3 years ago
A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo
Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

W=\int p \ dv

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

W_2=W_3=0

#For an isothermal change of state(ideal gas):

pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)

#for the expansion process:

W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J

W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52

W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J

Hence, the engine does 2234.63J per second.

8 0
3 years ago
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