If an athlete takes 60s to complete a race of 300m find his speed

Physics

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

5m/s

Explanation:

you just have to divide the distance covered and the time it takes to cover the distance.

v= d/t

= 300m/60s

=5m/s

You might be interested in

What does light means

Talja [164]

Answer:

Light is a source of illumination, whether a natural one (like the sun) or an artificial one (like your lamp). Like light itself, the word can take a lot of different forms — it can be a noun, an adjective, or a verb, and it can mean "bright" or "not heavy".

Explanation:

7 0

3 years ago

Read 2 more answers

Learning Goal:

enot [183]

Answer:

A. $U_0 = \dfrac{\epsilon_0 A V^2}{2d}$

B. $U_1 = \dfrac{\epsilon_0 A V^2}{6d}$

C. $U_2 = \dfrac{K\epsilon_0 A V^2}{2d}$

Explanation:

The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is

$C=\dfrac{\epsilon A}{d}$

$C$ is the capacitance, $A$ is the common plate area, $d$ is the plate separation and $\epsilon$ is the permittivity of the material between the plates.

For air or free space, $\epsilon$ is $\epsilon_0$ called the permittivity of free space. In general, $\epsilon=\epsilon_r \epsilon_0$ where $\epsilon_r$ is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum, $\epsilon_r=1$ .

The energy stored in a capacitor is the average of the product of its charge and voltage.

$U = \dfrac{QV}{2}$

Its charge, $Q$ , is related to its capacitance by $Q=CV$ (this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for $U$ ,