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kap26 [50]
4 years ago
12

What can acid rain do to buildings and statues

Chemistry
1 answer:
anastassius [24]4 years ago
5 0
<h3>Answer</h3>

The chemicals that acid rain contains can have damaging effects on objects like buildings, monuments, statues, and cars.

Its components can make paint to be peel, stone construction appears old, worn down which reduces the architectural value and beauty.

<h2>Explanation</h2>

Depending on how acidic the rain is, it can obliterate these constructions to a brutal degree.

First, components like sulfurous, sulfuric and nitric acids mix with air and rain. Then they react with calcite or calcium-based compounds in marble and limestone and dissolve calcite. 

The dry depositions of acidic particles contribute severely to the corrosion of construction materials, building paints, stones like marble, limestones and various type of granites.

Acid rains aggravate the life value of buildings and architectural structures.

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A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:
Anastasy [175]
It is a good thing that you already have answered the first question. Now, moving on to the second question, there exist an equation for the neutralization of acid by a base that is shown below,
                                          M₁V₁ = M₂V₂
Now, all the variables in the equation are given except for our unknown which is the V₂. Substituting the known values from the given above,
                                       (0.1 M)(25 mL) = (0.05 M)(V₂)
The value of V₂ from the equation above is 50 mL. Therefore, 50 mL of 0.05 M NaOH solution will be needed to completely react with HNO3. 
6 0
3 years ago
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The acceleration of a runner who accelerates from 0 m/s to 3 m/s in 12s
Naily [24]
4 m/s^2


I hope this helps! 
5 0
4 years ago
Why is it important for humans to monitor tides?
Tomtit [17]
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A perfectly spherical balloon occupied 35°C of neon gas under a pressure of 2 atm.
lutik1710 [3]

Answer:

V₂ =  116126.75 cm³

Explanation:

Given data:

Radius of balloon = 15 cm

Initial pressure = 2 atm

Initial temperature = 35 °C (35 +273 = 308K)

Final temperature = -20°C (-20+273 = 253 K)

Final pressure = 0.3 atm

Final volume = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

Initial volume of balloon:

V = 4/3πr³

V = 4/3×22/7×(15cm)³

V = 14137.17 cm³

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2 atm × 14137.17 cm³ × 253 K / 308 K × 0.3 atm

V₂ = 7153408.02 atm .cm³. K / 61.6 K.atm

V₂ =  116126.75 cm³

3 0
3 years ago
How many electrons does sodium lose in a chemical reaction ?
Dimas [21]
Neither it’s 10
I think this is right
8 0
3 years ago
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