Answer:
As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.
Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.
Below is the structures of possible minor products and the NMR spectrum respectively.
Possible Product A:
If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.
Possible Product B:
If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.
Possible Product C:
If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.
Possible Product D:
If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.
Answer:
search it up
Explanation:
khan academy hope this helps
Answer:
to me shes saying that you must read you vocab before reading your 6 paragraph article, then when you read that you will awnser some questions and they will all be in a student handout?
i kinda dont understand its confusing
Explanation:
You only can calculate the empirical formula with that information. I can not guarantee the empirical formula is going to be the same than the molecular formula. To be able to calculate the molecular formula you need the molecular mass or other information.
58.8/12= C = 4.9 => 4.9/1.96 = 2.5 => 2.5*2= 5
9.8/1= H = 9.8 => 9.8/1.96 = 5 => 5* 2= 10
31.4/16=O = 1.96 =>1.96/1.96 = 1 => 1*2 =2
empirical formula C5H10O2
Answer:
E
Explanation:
This is because all steps from A-D are important to obtain an accurate result