Question

An irregularly-shaped sample of aluminum (Al) is put on a balance and found to have a mass of 25.7 g. The student decides to use the water-displacement method to find the volume. The initial volume reading is 35.5 mL and, after the Al sample is added, the water level has risen to 41.7 mL. Find the density of the Al sample in g/mL. *

Answer 1

Answer:

4.14516129 g/mL

Explanation:

The density can be found with the following formula.

$d= \frac{m}{v}$

where $m$ is the mass and $v$ is the volume.

We know the mass is 25.7 grams. We must find the volume.

The volume is equal to the volume of water that is displaced. Subtract the initial volume from the final volume.

⇒ final volume - initial volume

The initial volume is 35.5 mL and the final volume is 41.7 mL.

⇒ 41.7 mL - 35.5 mL

⇒ 6.2 mL

The volume of the aluminum piece is 6.2 mL.

Now we know the mass and the volume.

$m= 25.7 g\\v=6.2 mL$

Substitute the values into the formula.

$d=\frac{m}{v}$

$d=\frac{25.7 g}{6.2 mL}$

$d=4.14516129 g/mL$

The density of the aluminum sample is 4.14516129 g/mL