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DedPeter [7]
3 years ago
6

**ANSWER ASAP**

Mathematics
1 answer:
spayn [35]3 years ago
7 0
They do all EXCEPT D, but the best answer is A because one can solve the system of equations this way
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If I have 9 employees and only 5 of them worked. What is my percentage
Charra [1.4K]
Percentage of working employees is 55.56
workings:5/9 x100
4 0
3 years ago
Find the median. 90, 88, 100, 82, 80.
gavmur [86]

Answer:

100 is the median for te above observations

<h2><em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>HELPED</u></em><em><u> </u></em></h2>

3 0
3 years ago
Read 2 more answers
A rectangle has a diagonal of 277 centimeters and a length of 252cm. How long is the width?
Crank

Answer:

width = 115 cm

Step-by-step explanation:

width² = 277² - 252²

width² = 76729 - 63504 = 13225

width = 115 cm

7 0
3 years ago
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Jan spent the day at the mall. She came home with $9.50. She spent $5.25 on earrings and 3 times that amount on a shirt. How muc
ki77a [65]

Answer:

She took $30.50 to the mall originally

Step-by-step explanation:

Let us solve the problem step by step

∵ She spent $5.25 on earrings

∵ The price of the shirt is 3 times the price of the earrings

∴ The price of the shirt = 3 × 5.25 = 15.75

∴ She spent $15.75 on the shirt

Find her total spending in the mall by adding the prices of earrings and the shirt

∴ She spent = 5.25 + 15.75 = 21

∴ She spent $21 on the mall

∵ She came home with $9.50

∵ She spent $21 on the mall

- Add them to find her original amount of money

∴ She took = 21 + 9.50 = 30.50

∴ She took $30.50 to the mall originally

5 0
3 years ago
You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that \sigma = 12000

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

M = z\frac{\sigma}{\sqrt{n}}

1000 = 1.96\frac{12000}{\sqrt{n}}

1000\sqrt{n} = 1.96*12

Dividing both sides by 1000:

\sqrt{n} = 1.96*12

(\sqrt{n})^2 = (1.96*12)^2

n = 553.2

Rounding up:

A sample size of 554 is needed.

5 0
3 years ago
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