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a_sh-v [17]
4 years ago
13

What is 4/11 divided by 4/9 as a fraction

Mathematics
1 answer:
vovikov84 [41]4 years ago
5 0

Answer:

9/11

Step-by-step explanation:

To divide, you have to flip the dividend.

So, 4/9 would become 9/4

Then you multiply 4/11 by 9/4

This would give you 36/44

Simplify.

18/22

Simplify some more.

9/11

Hope I helped :)

Please consider Brainliest :)

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The mass of a glass bottle is 250g. Its capacity is 500mL. What is the mass when it is full of water?
Nadya [2.5K]

Answer:

d

Step-by-step explanation:

the bottle is 250g and it can carry 500ml.

so you add the bottles weight (250) and the capacity (500) which equals

=750

4 0
3 years ago
Read 2 more answers
What is x 5/9 of x is 90<br>help assap
blsea [12.9K]

Answer:

<h2>162</h2>

Step by step explanation

\frac{5}{9} x  = 90

Multiply both sides of equation by 9/5

\frac{9}{5}  \times  \frac{5}{9} x =  \frac{9}{5}  \times 90

Reduce the numbers with Greatest common factor 9

\frac{1}{5}  \times 5x =  \frac{9}{5}  \times 90

Reduce the numbers with G.C.F 5

x =  9  \times 18

Multiply the numbers

x = 162

Hope this helps..

Best regards!!

5 0
3 years ago
Read 2 more answers
A manager asked her employees how many times they had given blood in the last year. The results of the survey are given below. T
stira [4]

<u>Complete Question</u>

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

Answer:

1.61

Step-by-step explanation:

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

We want to determine the mean number of times a person gave blood.

Expected Value, E(x)=\sum x_i\cdot P(x_i)

=(0 \times 0.33)+ (1 \times 0.24)+(2\times0.16)+(3\times0.12)+(4\times0.08)+(5\times0.05)+(6\times0.02)\\=0+0.24+0.32+0.36+0.32+0.25+0.12\\=1.61\\

The mean number of times a person gave blood based on this survey is 1.61.

4 0
4 years ago
PLEASE HELP!! MEEEEE 1
mestny [16]

Answer:

(1,2) (3,2) ( 5,2)

Step-by-step explanation:

Each input value can only go to one output value

The only one that has each input only going to one output is (1,2) (3,2) ( 5,2)

8 0
3 years ago
C=1/21.22.23+1/22.23.24+................+1/200.201.202<br><br> . = là dấu nhân
Aneli [31]

It looks like you have to find the value of the sum,

C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}

so that the <em>n</em>-th term in the sum is

\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}

for 1 ≤ <em>n</em> ≤ 180.

We can then write the sum as

\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}

Break up the summand into partial fractions:

\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}

Combine the fractions into one with a common denominator and set the numerators equal to one another:

1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)

Expand the right side and collect terms with the same power of <em>n</em> :

1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c

Then

<em>a</em> + <em>b</em> + <em>c</em> = 0

43<em>a</em> + 42<em>b</em> + 41<em>c</em> = 0

462<em>a</em> + 440<em>b</em> + 420<em>c</em> = 1

==>   <em>a</em> = 1/2, <em>b</em> = -1, <em>c</em> = 1/2

Now our sum is

\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)

which is a telescoping sum. If we write out the first and last few terms, we have

<em>C</em> = 1/(2×21) - 1/22 <u>+ 1/(2×23)</u>

… … + 1/(2×22) - 1/23 <u>+ 1/(2×24)</u>

… … <u>+ 1/(2×23)</u> - 1/24 <u>+ 1/(2×25)</u>

… … <u>+ 1/(2×24)</u> - 1/25 <u>+ 1/(2×26)</u>

… … + … - … + …

… … <u>+ 1/(2×198)</u> - 1/199 <u>+ 1/(2×200)</u>

… … <u>+ 1/(2×199)</u> - 1/200 + 1/(2×201)

… … <u>+ 1/(2×200)</u> - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

<em>C</em> = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

<em>C</em> = 1/42 - 1/44 - 1/402 + 1/404

<em>C</em> = 1,115/1,042,118 ≈ 0.00106994

4 0
3 years ago
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