Question

In principle, the motion of a simple pendulum and an object on an ideal spring can both be used to provide the basic time interval or period used in a clock. Which of the two kinds of clocks becomes more inaccurate when carried to the top of a high mountain?

Answer 1

Answer:

Explanation:

The time period of the pendulum containing simple pendulum is given by

$T = 2\pi \sqrt{\frac{L}{g}}$

where, L is the length of the pendulum and g is the value of acceleration due to gravity.

The time period of the clock using the spring mechanism is given by

$T = 2\pi \sqrt{\frac{m}{k}}$

where, m is the mass of the block attached to the spring and k is the spring constant.

here we observe the time period of the pendulum depends on the value of acceleration due to gravity. The value of acceleration due to gravity decreases as we go on the heights that means when the clock is taken to the mountain, the value of g decreases and thus, the value of time period increases and the clock runs slow.

So, the clock containing the spring system gives the accurate reading rather than the clock containing simple pendulum.

Answer 2

Answer:

Simple-pendulum clock

Explanation:

A simple pendulum clock is defined as a clock that is comprised of a fixed mass, that is hanged at one end, which is commonly known as the pivot with the help of a string that is comprised of a definite length. This pendulum is then allowed to swing back and forth by simply displacing it at a certain angle and thereby releasing it. This results in the periodic motion.

The time period of this type of clock directly depends on its rate of acceleration under the influence of gravitational force. Due to this, it is considered to be an inaccurate clock when used at the top of high mountains.