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3 years ago

Which is a future NASA research project? Check all that apply.

Physics

1 answer:

Nat2105 [25]3 years ago

6 0

All of the given options represent NASA future projects:

Use a probe to collect data- Parker Solar Probe will be the first-ever mission to study the Sun from such a small distance. The spacecraft will travel directly into the Sun's atmosphere about 4 million miles from the surface.

Improve aviation technology- NASA is currently working on the development of the new experimental aircraft X-plane which will prove the dramatic benefits of advanced technologies in piloted flight.

Conduct research from a space station- Humans are already living and working on board of the International Space Station which is one-of-a-kind research laboratory in microgravity. A portion of the astronauts time aboard the space station has been designated for national laboratory investigations.

Collect samples on an asteroid- First asteroid sample return mission, OSIRIS-REx, arrives at the near-Earth asteroid Bennu in December 2018 and should return a sample for study in 2023.

Conduct an unmanned space mission- InSight Mars lander is set to study the planet’s interior. The Mars 2020 rover will search for signs of past microbial life, gather samples for future return to Earth and investigate resources. The James Webb Space Telescope will be the premier observatory of the next decade, studying every phase in the history of our Universe in infrared

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An open system starts with 52 J of mechanical energy. The energy changes

spayn [35]

Answer:

I think the answer is D,54 joules

5 0

3 years ago

A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 375 N

spayn [35]

Answer:

The conservation of energy should be used to answer this question.

At the position where the spring is unstretched, the elastic potential energy of the spring is zero.

$K_1 + U_1 - W_f = K_2 +U_2\\K_1 - W_f = U_2$

since $U_1$ and $K_2$ is equal to zero.

$W_f = F_fx\\\\U_2 = \frac{1}{2}kx^2\\\\19 - (10)x = \frac{1}{2}(375)x^2\\\\375x^2 + 20x - 38 = 0$

The roots of this quadratic equation can be solved by using discriminant.

$\Delta = b^2 - 4ac\\x_{1,2} = \frac{-b \pm \sqrt{\Delta}}{2a}$

$x_1 = -0.346\\x_2 = 0.292$

We should use the positive root, so

x = 0.292 m.

We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.

$K_2 + U_2 - W_f = K_3 + U_3\\U_2 - W_f = K_3$

since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.

$\frac{1}{2}kx^2 - F_fx = K_3\\K_3 = 15.987 - 2.92 = 13.067 J$

Explanation:

In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.

In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).

8 0

3 years ago

If an object weighs 300 N on earth, what is it’s mass on the moon?

inna [77]

Answer:

The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.

Explanation:

Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:

(weight) = (mass) x (gravitational acceleration)

We are to find the mass, knowing the weight on Earth to be 300N:

(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg

The mass of the object is 30.61kg.

The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.

If the question were what is its weight on the Moon, the answer would be

(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N

which is about 1/6 of the object's weight on the Earth.

4 0

3 years ago

A student wishes to record a 7.5-kilogram watermelon colliding with the ground. Calculate how far the watermelon must fall freel

algol [13]

Answer:

42.86m

Explanation:

The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

$\frac {Vf^{2}-Vo^2}{2.g} =Y$

where

Vf=29m/s= final speed

Vo= initial speed=0m/S

g=gravity=9.81m/s^2

Y= distance traveled(m)

solving

$\frac {Vf^{2}-Vo^2}{2.g} =Y\\\frac {(29m/s)^{2}-(0m/s)^2}{2(9.8m/s^2)} =Y\\Y=42.86m\\$

the distance traveled by watermelon is 42.86m

5 0

4 years ago

This problem has been solved!

irakobra [83]

Answer:

The correct answer is option '5': The type of metal from which the plate is made.

Explanation:

According to the principle of photoelectric effect we know that electron's are only emitted from a surface of metal if the frequency of the light is larger than a threshold frequency that depends on the metal and is known as threshold function of the metal. The ejection of the electrons is independent of intensity of the incident light meaning any light of frequency lower than work function will not eject electrons from the metal no matter whatever the intensity of the light, or the surface area or thermal conductivity, time of illumination.

5 0

3 years ago