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Alisiya [41]
3 years ago
15

Tire inflation is very important to the safe and economical operation of any vehicle. Technician A says that the tire pressure s

hould never exceed the maximum pressure imprinted on the sidewall of the tire. Technician B says to inflate tires to the pressures recommended on the tire information decal or placard on the drivers door. Which technician is correct? Group of answer choices: a) Technician A only b) Tehnician B only c) Both tehnicians A and B d) Neither tehnicians A nor B.
Physics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

The correct option is;

c) Both technicians A and B

Explanation:

Normally the pressure required for a normally inflated tire is included on the side or sidewall of the tire along with the instruction as to the qualification and training required to inflate the vehicle tire. Other information on the sidewall includes the tire model, brand name and manufacturer.

The proper inflation pressure can also be located on the tire information manual or decal as well on the door on the driver's side.

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A long, straight wire lies in the plane of a circular coil with a radius of 0.018 m. the wire carries a current of 5.6 a and is
iris [78.8K]
(a) The net flux through the coil is zero.
In fact, the magnetic field generated by the wire forms concentric circles around the wire. The wire is placed along the diameter of the coil, so we can imagine as it divides the  coil into two emisphere. Therefore, the magnetic field of the wire is perpendicular to the plane of the coil, but the direction of the field is opposite in the two emispheres. Since the two emispheres have same area, then the magnetic fluxes in the two emispheres are equal but opposite in sign, and so they cancel out when summing them together to find the net flux.

(b) If the wire passes through the center of the coil but it is perpendicular to the plane of the wire, the net flux through the coil is still zero.
In fact, the magnetic field generated by the wire forms concentric lines around the wire, so it is parallel to the plane of the coil. But the flux is equal to
\Phi = BA \cos \theta
where \theta is the angle between the direction of the magnetic field and the perpendicular to the plane of the coil, so in this case \theta=90^{\circ} and so the cosine is zero, therefore the net flux is zero.
5 0
3 years ago
Electric charges can only be transferred through a process called conduction.true or false
umka21 [38]

I'm going to say false hope that helped

5 0
3 years ago
Read 2 more answers
An elevator traveled 15 floors (150 ft) at a speed of 4.5 m/s. What additional information is needed to determine the velocity o
vladimir2022 [97]

<em>Answer:</em>

<em>Velocity is vector quantity.So it needs direction in addition to speed.</em>

<em>Explanation:</em>

<em>The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of its speed and direction of motion. </em>

4 0
3 years ago
Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
IceJOKER [234]

Answer:

Explanation:

See the attachment for the details.  A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times.  The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.  

The individual driving times and distances are summed to provide:

(<u>a) How far did he travel?</u>

103 km

<u>(b) What was his average speed?</u>

12.88 km/h

<u>(c) What was his displacement?</u>

73.82 km

<u>(d) What was his average velocity?</u>

9.228 km/h

8 0
2 years ago
Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re
leva [86]

Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

The conversion from feet to inches is 1 ft is equal to 12 inches. In this case, 5 ft are equal to 60 inches.

F_l=\frac{25*60}{33}

F_l=45.5 lbs

7 0
3 years ago
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