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3 years ago

7

Jason rides his bicycle 1,200 meters east to the grocery store. He then turns around and travels 760 meters west to meet his fri

end. What are his total distance and his displacement?

1 answer:

KiRa [710]3 years ago

6 0

Since displacement is a vector quantity, it depends on direction as well as magnitude.

Taking displacement towards east as positive and towards west as negative,
Total displacement = 1200 + (-760) = 440 meters.

Since distance is a scalar quantity, it depends only upon magnitude.
Total distance = 1200 + 760 = 1960 meters.

Hope this cleared your doubt, feel free to ask any questions regarding this and have a nice day ahead! :)

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To calibrate your calorimeter cup, you first put 45 mL of cold water in the cup, and measure its temperature to be 24.7 °C. You

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First we have to calculate the mass of cold water.

As we know that the density of water is 1 g/mL. The volume of cold water is 45 mL.

$Density=\frac{Mass}{Volume}$

$Mass=Density\times Volume=1g/mL\times 45mL=45g$

Now we have to calculate the heat change of cold water.

Formula used :

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat change of cold water = ?

m = mass of cold water = 45 g

c = specific heat of water = $4.184J/g^oC$

$T_1$ = initial temperature of cold water = $24.7^oC$

$T_2$ = final temperature = $33.4^oC$

Now put all the given value in the above formula, we get:

$Q=45g\times 4.184J/g^oC\times (33.4-24.7)^oC$

$Q=1638.036J=1.6\times 10^3J$

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3 years ago

A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr

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Y=Yo+Voyt+1/2at^2
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sqrt(.55/4.9)=t
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3 years ago

A soccer player takes a corner kick, lofting a stationary ball 30.0° above the horizon at 18.0 m/s. If the soccer ball has a mas

Radda [10]

Answer:

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Explanation:

Given:

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time of application of force, $t=5.3\times 10^{-2}\,s$

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$\Delta p=0.425\times 18$

$\Delta p=7.65 \,kg.m.s^{-1}$

Now the components:

$\Delta p_x= 7.65\times cos 30^{\circ}$

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similarly

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also, impulse

$I=F\times t$ .........................(2)

where F is the force applied for t time.

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$F_x=144.3396\times cos 30^{\circ}$

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&

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