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Marrrta [24]
3 years ago
7

Jason rides his bicycle 1,200 meters east to the grocery store. He then turns around and travels 760 meters west to meet his fri

end. What are his total distance and his displacement?
Physics
1 answer:
KiRa [710]3 years ago
6 0
Since displacement is a vector quantity, it depends on direction as well as magnitude.

Taking displacement towards east as positive and towards west as negative,
Total displacement = 1200 + (-760) = 440 meters. 

Since distance is a scalar quantity, it depends only upon magnitude.
Total distance = 1200 + 760 = 1960 meters. 

Hope this cleared your doubt, feel free to ask any questions regarding this and have a nice day ahead! :)
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Answer:

0.29713 m/s

Explanation:

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v = Velocity

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mg-N=\dfrac{mv^2}{r}\\\Rightarrow mg-\dfrac{mg}{2}=\dfrac{mv^2}{r}\\\Rightarrow v=\sqrt{r(g-\dfrac{g}{2})}\\\Rightarrow v=\sqrt{0.018\times (9.81-\dfrac{9.81}{2})}\\\Rightarrow v=0.29713\ m/s

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3 years ago
R,=4.00 R, = 1000.00
lisabon 2012 [21]

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3 years ago
The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinet
patriot [66]

6050 J is the kinetic energy at D

<u>Explanation:</u>

In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,

           K . E=\frac{1}{2} \times m \times v^{2}

Where,

m - mass of an object

v - velocity of the object

Here,

Given data:

m  = 100 kg

v = 11 m/s

By substituting the given values in the above equation, we get

            K . E=\frac{1}{2} \times 100 \times(11)^{2}=\frac{1}{2} \times 100 \times 121=\frac{12100}{2}=6050\ \mathrm{J}

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3 years ago
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alex41 [277]

Answer:

30643 J

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A = Area = 1\ mm^2

Magnitude of magnetic field is given by

B_0=\dfrac{E_0}{c}\\\Rightarrow B_0=\dfrac{1.52\times 10^{11}}{3\times 10^8}\\\Rightarrow B_0=506.67\ T

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The energy it delivers is 30643 J

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