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denpristay [2]
3 years ago
6

A roller coaster car is going over the top of a 15-m-radius circular rise. The passenger in the roller coaster has a true weight

of 600 N (therefore a mass of 61.2 kg). At the top of the hill, the passengers "feel light," with an apparent weight of only 360 N. How fast is the coaster moving
Physics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

v = 7.67 m/s

Explanation:

The equation for apparent weight in the situation of weightlessness is given as:

Apparent Weight = m(g - a)

where,

Apparent Weight = 360 N

m = mass passenger = 61.2 kg

a = acceleration of roller coaster

g = acceleration due to gravity = 9.8 m/s²

Therefore,

360 N = (61.2 kg)(9.8 m/s² - a)

9.8 m/s² - a = 360 N/61.2 kg

a = 9.8 m/s² - 5.88 m/s²

a = 3.92 m/s²

Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:

a = v²/r

where,

a = centripetal acceleration = 3.92 m/s²

v = speed of roller coaster = ?

r = radius of circular rise = 15 m

Therefore,

3.92 m/s² = v²/15 m

v² = (3.92 m.s²)(15 m)

v = √(58.8 m²/s²)

<u>v = 7.67 m/s</u>

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Answer:

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Explanation:

Using the Physics reference sheet the formula for Potential energy is

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2 years ago
a force is applied to a box of 10.0 kg for 4.0 s. the box goes from rest to 25 m/s in that time. What is the magnitude of that f
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Given:

m(mass of the box)=10 Kg

t(time of impact)=4 sec

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Now we know that

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8 0
3 years ago
Par 1/2
BaLLatris [955]

part 1

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part 2

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convert PE to Mt:

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KengaRu [80]
Answer:
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Explanation:
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3 years ago
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