The radius of each jawbreaker is approximately 0.68 cm.
<h3>Volume of a sphere;</h3>
where
r = radius
Therefore,
23 g = 32.3 cm³
0.94 g = ?
cross multiply
volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³
Therefore,
volume of each jawbreaker = 4 /3 πr³
1.32 = 4 / 3 × 3.14 × r³
r³ = 1.32 /4.18666666667
r³ = 0.31533683707
r = ∛0.31533683707
r = 0.680651651 = 0.68
Therefore, the radius of each jawbreaker is approximately 0.68 cm.
learn more on radius here: brainly.com/question/19172427
Answer:
0.5 m
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 0.060 kg
Period (T) = 1.4 s
Lenght (L) =?
NOTE:
1. Acceleration due to gravity (g) = 10 m/s²
2. Pi (π) = 3.14
The length of the pendulum can be obtained as follow:
T = 2π√(L/g)
1.4 = 2 × 3.14 × √(L/10)
1.4 = 6.28 × √(L/10)
Divide both side by 6.28
1.4 / 6.28 = √(L/10)
Take the square of both side
(1.4 / 6.28)² = L/10
Cross multiply
L = 10 × (1.4 / 6.28)²
L = 0.5 m
Therefore, the length of the pendulum is 0.5 m
Answer:
The group one element are called alkali because when they dissolved in water they form alkaline solutions
Alpine glaciers<span> is the answer
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