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ryzh [129]
3 years ago
6

A chain 72 meters long whose mass is 29 kilograms is hanging over the edge of a tall building and does not touch the ground. How

much work is required to lift the top 14 meters of the chain to the top of the building?
Use that the acceleration due to gravity is 9.8 meters per second squared. Your answer must include the correct units.
Physics
1 answer:
dangina [55]3 years ago
5 0

Answer:

Work done required is 3567.2 J

Explanation:

Given :

Length of chain, l = 72 m

Mass of chain, M = 29 kg

Linear mass density of chain, μ = \frac{Mass\ of\ chain }{Length\ of\ chain} = \frac{29}{72}  = 0.40 kg/m

Let x be the length of the chain which lift to the top of the building.

Work done required to lift the chain is equal to the potential energy of the chain.

W = ∫μg (72 - x ) dx

Here g is acceleration due to gravity.

The limit of integration is from 0 to 14.

W = μg ( 72x - x²/2)

Substitute 0.40 kg/m for μ, 9.8 m/s² for g and 14 m for x in the above equation.

W = 0.40\times9.8\times(72\times14\ - \frac{14^{2} }{2})

W = 3567.2 J

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Imma say go with C (:
5 0
4 years ago
You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r
sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law n_1sin\theta_1=n_2sin\theta_2, where if n_1 is the <em>refractive index</em> of the medium containing the <em>incident ray</em>, \theta_1 would be the <em>incident angle</em>, and if n_2 is the <em>refractive index</em> of the medium containing the <em>refracted ray</em>, \theta_2 would be the <em>refraction angle</em>, which we want, so we do:

sin\theta_2=\frac{n_1}{n_2}sin\theta_1

And finally:

\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)

We then insert our values:

\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)=Arcsin(\frac{1}{3.325}sin(0.478rad))=arcsin(0.13834714686&#10;)=0.139 rad

6 0
3 years ago
A lifeguard on a beach observes that waves have a speed of 7 m/s and a distance of 4.6m between wave crests. what is the period
Pepsi [2]

Answer:

0.657 seconds

Explanation:

speed of wave= wavelength / time period

so

time period= wavelength / speed

= 4.6/7

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4 0
3 years ago
A parallel-plate capacitor connected to a battery becomes fully charged. After the capacitor from the battery is disconnected, t
Valentin [98]

Answer:

C.)The energy stored in the capacitor doubles its original value.

Explanation:

The capacitance of a capacitor is given by:

C₁ = ∈A/d...............................(1)

If the distance between the plates is doubled

C₂ = ∈A/2d.............................(2a)

From equations (1) and (2), the relationship between C₁ and C₂ is:

C₂ = C₁/2....................................(2b)

The original  Energy stored in the capacitor is given by :

E₁ = Q²/2C₁...............................(3)

On doubling the separation between the capacitance plates

E₂ = Q²/2C₂...............................(4a)

E₂ = Q²/2  *  1/C₂........................(4b)

Putting equation (2b) into (4b)

E₂ = Q²/2  *  2/C₁

E₂ = Q²/C₁.....................................(5)

Comparing equations (3) and (5)

E₂ = 2E₁

Therefore, the energy stored in the capacitor doubles its original value

4 0
4 years ago
If a water wave completes one cycle in 2 seconds, what is
Novay_Z [31]

The period of a wave is the time it takes the wave to complete one cycle (at a fixed location).

So if a wave completes one cycle in <em>2 seconds</em>, then that is its period.

8 0
3 years ago
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