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schepotkina [342]
3 years ago
3

Superman is flying 54.5 m/s when he sees a train about to fall into a river 850 m away. He must reach the train in 4.22 s. What

acceleration does he need? (Unit = m/s^2)
Physics
1 answer:
ivann1987 [24]3 years ago
5 0

69.66m/s²

Explanation:

Given parameters:

Initial velocity, U of superman = 54.5m/s

distance, s = 850m

time to reach train, t = 4.22s

Unknown

Acceleration, a = ?

Solution:

To solve this problems, we have to use on of the equations of kinematics:

          S = ut + \frac{1}{2} at²

The equation above is the perfect fit to solve our problem.

Since a is the unknown, we plug in the known parameters:

     850 = (54.5 x 4.22) + ( \frac{1}{2} x a x 4.22²)

     850 = 229.99‬ + (0.5  x 4.22² x a)

     850 = 229.99 + 8.9a

  8.9a = 850 - 229.99

  8.9a = 620

       a = 69.66m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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Consider your moment of inertia about a vertical axis through the center of your body, both when you are standing straight up wi
jeka94

Answer:

     I₁ / I₂ = 1.43

Explanation:

To find the relationship of the two inertial memits, let's calculate each one, let's start at the moment of inertia with the arms extended

Before starting let's reduce all units to the SI system

       d₁ = 42 in (2.54 10⁻² m / 1 in) = 106.68 10⁻² m

       d₂ = 38 in = 96.52 10⁻² m

The moment of inertia is a scalar quantity for which it can be added, the moment of total inertia would be the moment of inertia of the man (cylinder) plus the moment of inertia of each arm

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Man indicates that we can approximate them to a cylinder where the average diameter is

         d = (d₁ + d₂) / 2

         d = (106.68 + 96.52) 10-2 = 101.6 10⁻² m

The average radius is

         r = d / 2 = 50.8 10⁻² m = 0.508 m

The mass of the trunk is the mass of man minus the masses of each arm.

        M = M_man - 0.2 M_man = 80 (1-0.2)

        M = 64 kg

The moments of inertia are:

A cylinder with respect to a vertical axis:         Ic = ½ M r²

A rod that rotates at the end:                            I_arm = 1/3 m L²

Let us note that the arm rotates with respect to man, but this is at a distance from the axis of rotation of the body, so we must use the parallel axes theorem for the moment of inertia of the arm with respect to e = of the body axis.

           I1 = I_arm + m D²

Where D is the distance from the axis of rotation of the arm to the axis of the body

          D = d / 2 = 101.6 10⁻² /2 = 0.508 m

Let's replace

          I₁ = ½ M r² + 2 [(1/3 m L²) + m D²]

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          I₂ = ½ 64 0.508² + 2 8 0.508²

          I₂ = 8,258 + 4,129

          I₂ = 12,387 kg m² / s²

The relationship between these two magnitudes is

          I₁ / I₂ = 17,717 /12,387

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