Answer:
4.02 s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 35°
Initial velocity (u) = 50 m/s
Acceleration due to gravity (g) = 10 m/s²
Time of flight (T) =?
The time of flight of the arrow can be obtained as follow:
T = 2uSineθ / g
T = 2 × 35 × Sine 35 / 10
T = 70 × 0.5736 / 10
T = 7 × 0.5736
T = 4.02 s
Therefore, the time taken for the arrow to return is 4.02 s
I think b is the answer but im not 100% sure
There is not enough information to answer the question
Answer:
a) a right triangle, b) x = 0.167 m
Explanation:
a) It is asked to find which geometry figure describes the movement of the ant.
Let's use trigonometry with the angles measured in radians
tan θ = y / x
tan θ = 6/10
θ = tan⁻¹ 0.6
θ = 0.54 rad
this value is equal to the upward slope therefore the geometric body that describes the movement is a right triangle
b) it is asked to find the horizontal displacement for a vertical displacement of y = 0.1 cm x = y / tan tea
x = 0.1 / tan 0.54
x = 0.1668 m
x = 0.167 m
