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Sholpan [36]
4 years ago
9

A force of 26.4lb is applied to an area of 1.71 in2. What is the pressure?

Chemistry
1 answer:
aleksandrvk [35]4 years ago
5 0

Answer:

Pressure, P = 15.4 lb/in²

Explanation:

Given that,

Force applied, F = 26.4 lb

Area of cross section, A = 1.71 in²

To find,

Pressure.

Solution,

Pressure is equal to force per unit area of cross section.

P=\dfrac{F}{A}\\\\P=\dfrac{26.4\ lb}{1.71\ in^2}\\\\P=15.43\ lb/in^2\\\\P=15.43\ Pa

Hence, the correct option is (a) "15.4 lb/in²".

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3 years ago
Becquerel placed photographic paper in a drawer with some radioactive rocks and discovered that the amount of exposure on the pa
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5 0
2 years ago
I need help with this please!!
GenaCL600 [577]

Answer:

Option no 3

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3 0
4 years ago
Read 2 more answers
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
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