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3 years ago

In what type of reaction will an acid and a base react with each other

2 answers:

6 0

When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acidcombines with the OH(-) anion of the base to form water.

Otrada [13]3 years ago

3 0

An Acid and a Base react together and cause Neutralization to occur.

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What are isotopes please help

NikAS [45]

Answer:

Isotopes are atoms of the same element with the same number of protons but different number of neutrons.

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6 0

3 years ago

Read 2 more answers

Which element has their valence electron farthest from the nucleus?

Iteru [2.4K]

The answer is Rubidium (Rb)

4 0

3 years ago

For the reaction A + B + C → D + E, the initial reaction rate was measured for various initial concentrations of reactants. The

babymother [125]

Answer : The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B+C\rightarrow D+E$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.0\times 10^{-4}=k(0.20)^a(0.20)^b(0.20)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-3}=k(0.20)^a(0.20)^b(0.60)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-3}=k(0.40)^a(0.20)^b(0.20)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-3}=k(0.40)^a(0.40)^b(0.20)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-3}}{2.4\times 10^{-3}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Thus,

The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

5 0

3 years ago

I need help pls brainless if right

tatuchka [14]

Answer: C

Jane Goodall observed the chimpanzees. She noted the chimpanzees, and she studied their bodies closely. This is an example of investigation.

Hope this helps you!

8 0

3 years ago

Anna got fed up and decided to put some of her classmates in a big box. She shoved Riley, Justin, and Paul into the box and tape

Katena32 [7]

Answer:

Explanation:

Total force of friction between the box and the floor = 400 N

Force each student can apply = 32 N

Let the number of students required be x.

So, students required to make the box start moving

= 400 N < 32xN

= 400N/32N < x

= 12.5 < x

So, more than 12.5 students will be required. Since 12.5 students is not physically possible, so we will take the nearest whole number that is greater than 12.5, i.e, 13. So, 13 students will be required to shove the box.

3 0

3 years ago