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2 answers:
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Complete Question
A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane
The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?
Answer:
The mass of caffeine extracted is
Explanation:
From the question above we are told that
The K value is
The mass of the caffeine is
The volume of water is
The volume of caffeine is
The number of times the extraction was done is n = 3
Generally the mass of caffeine that will be extracted is
substituting values
Answer:
Reaction 1 is balanced but 2 is not balanced , the balance equation are :
1.
2.
Explanation:
Balanced Equations : These are the equation which follows the law of conservation of mass .
The total number of atoms present in reactant is equal to total number of atoms present in product.
1.
This is acid - base type reaction where
act as Acid
act as weak base
Reactant : ,
Number of atoms of :
C = 2 () + 1 (
)
= 2 + 1
= 3
H = 4() + 1 (
)
= 4 + 1
5
O = 2() + 3 (
)
= 5
Na = 1 ()
= 1
Product : ,
,
Number of atoms :
C = 1() + 2(
)
= 1 + 2
= 3
H = 2() + 3(
)
= 2 + 3
= 5
O = 1() + 2(
)
+2(
= 1 + 2 + 2
= 5
Na = 1(
= 1
Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction
2.
This is double displacement reaction .
Check the balancing in both reactant and products should be :
Na = 2
H = 2
Ca = 1
C = 2
O = 6
Cl = 2