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forsale [732]
3 years ago
7

A 2.00-g sample of a large biomolecule was dissolved in 15.0 g carbon tetrachloride. the boiling point of this solution was dete

rmined to be 77.85c. calculate the molar mass of the biomolecule. for carbon tetrachloride, the boiling-point constant is 5.03c kg/mol, and the boiling point of pure carbon tetrachloride is 76.50c.
Chemistry
1 answer:
Katarina [22]3 years ago
5 0
We will use boiling point formula:

ΔT = i Kb m 

when ΔT is the temperature change from the pure solvent's boiling point to the boiling point of the solution = 77.85 °C - 76.5 °C = 1.35

and Kb is the boiling point constant =5.03

and m = molality 

i = vant's Hoff factor

so by substitution, we can get the molality:

1.35 = 1 * 5.03 * m

∴ m = 0.27

when molality = moles / mass  Kg

           0.27 = moles /  0.015Kg

∴ moles = 0.00405 moles

∴ The molar mass = mass / moles
                               = 2 g /  0.00405 moles 
                               = 493.8 g /mol
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