Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
Answer:
x = 114
Step-by-step explanation:
180 - 105 = 75
39 + 75 = x
x = 114
Take any 2 points the answer will be the same.
For point 2 and 3 : (-4)-(2)/(0)-(-1) = -6
the answer is -6
Answer:
0.12 is the required probability.
Step-by-step explanation:
We are given the following in the question:
A: next component brought in for repair is an audio component
B: event that the next component is a compact disc player
![B \in A](https://tex.z-dn.net/?f=B%20%5Cin%20A)
![P(A)= 0.6\\P(B) =0.05](https://tex.z-dn.net/?f=P%28A%29%3D%200.6%5C%5CP%28B%29%20%3D0.05)
We have to evaluate:
![P(B|A) = \dfrac{P(B\cap A)}{P(A)}\\P(B|A) = \dfrac{P(B)}{P(A)}\\\\P(B|A) = \dfrac{0.05}{0.6} = 0.12](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cdfrac%7BP%28B%5Ccap%20A%29%7D%7BP%28A%29%7D%5C%5CP%28B%7CA%29%20%3D%20%5Cdfrac%7BP%28B%29%7D%7BP%28A%29%7D%5C%5C%5C%5CP%28B%7CA%29%20%3D%20%5Cdfrac%7B0.05%7D%7B0.6%7D%20%3D%200.12)
0.12 is the required probability.
Answer:
<em>1, 2, 3</em>
Step-by-step explanation:
Of the three units, the <em>kilogram</em> is the largest and the <em>milligram</em> is the smallest. The prefix “<em>kilo</em>” means a thousand and “<em>milli</em>” means one-thousandths.
1,000,000mg = 1kg
1kg = 1,000g