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3 years ago

Whoever answers this first gets brainliest Pls help ASAP

Mathematics

2 answers:

Vaselesa [24]3 years ago

8 0

Answer:

1. Rational Number

2. Irrational Number

3. Terminating Decimal

4. Repeating Decimal

Step-by-step explanation:

A Rational Number can be written as a ratio of two integers. For example, as a simple fraction. That leaves us for the answer to the second one as irrational. To terminate means to end, so a terminating decimal is a decimal that does not go on forever. Whereas, a repeating decimal continues repeating forever (or indefinitely).

I would like to apologize in advance if any of these were incorrect.

Mandarinka [93]3 years ago

7 0

Answer:

Terminating goes to 3

Repeating goes to 4

Rational goes to 1

Irrational goes to 2

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The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia

sveta [45]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Technician __Shutdown

Taylor, T___4

Rousche, R _ 3

Hurley, H__ 3

Huang, Hu___2

Gupta, ___ 5

The Numbe of samples of 2 possible from the 5 technicians :

We use combination :

nCr = n! ÷ (n-r)!r!

5C2 = 5!(3!)2!

5C2 = (5*4)/2 = 10

POSSIBLE COMBINATIONS :

TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG

Sample means :

TR = (4+3)/2 = 3.5

TH = (4+3)/2 = 3.5

THu = (4+2) = 6/2 = 3

TG = (4 + 5) = 9/2 = 4.5

RH = (3+3) = 6/2 = 3

RHu = (3+2) /2 = 2.5

RG = (3 + 5) = 8/2 = 4

HHu = (3+2) = 2.5

HG = (3+5) = 8/2 = 4

HuG = (2+5) / 2 = 3.5

Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4

Population mean :

(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4

Population Mean and mean of sample means are the same.

This distribution should be approximately normal.

7 0

3 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

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3 years ago

How many ways can you arrange the letters in the word prime?

Jobisdone [24]

There are 5 letters in the word "prime"

Imagine we had 5 slots to fill. They are empty initially.
Slot 1 has 5 choices to pick from
Once we pick a letter, we have 4 choices left over for slot 2
Slot 3 will have 3 choices
Slot 4 will have 2 choices
Slot 5 will have 1 choice

We have this countdown: 5,4,3,2,1

which multiplies out to 5*4*3*2*1 = 120

There are 120 unique ways to arrange the letters. Order matters. Because order matters, this is a permutation.

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3 years ago

If a city with a population of 700,000 doubles in size every 71 years, what will the population be 213 years from now?

hichkok12 [17]

Answer:

2,100,000

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jim and Sean went to the diner and bought two egg scrambles. Jim also got a cup of coffee for a dollar. If their total bill was

Alex73 [517]

Answer:

If only Jim purchased a cup of coffee, we will subtract its cost from the total;

9.50 - 1.00 = 8.50

Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.

Since they both bought eggs, then 2x = 8.50

x = $4.25, the price for each egg scramble

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3 years ago