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3 years ago

For how many minutes of calls with the cost of the two plans be equal?

Mathematics

1 answer:

Maurinko [17]3 years ago

4 0

Answer:

Let x = the number of minutes of calls

For Plan 1, we know that the monthly charge is 8 + 0.18x

For Plan 2, the monthly charge is 23 + 0.14x

To determine when the cost of the two plans will be equal, we set up the following equation:

8 + 0.18x = 23 + 0.14x

Can you solve for x, Alyssa?

Step-by-step explanation:

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3 years ago

UICHL Idlic 3_21 x 28 x= What does x equal

Advocard [28]

Answer:

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Step-by-step explanation:

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3 years ago

Elementary Algebra Skill

mr_godi [17]

The answer is a = $\frac{4}{-3}$

Step-by-step explanation:

1. Convert the mixed fraction to an improper fraction

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2 $\frac{2}{3}$ will be $\frac{8}{3}$

2. Now the equation is,

$\frac{3}{2}$ a - $\frac{4}{3}$ a = $\frac{10}{3}$ + $\frac{8}{3}$ a

3. Take LCM on both sides.

For the left side, multiply the first fraction by $\frac{3}{3}$ and multiply the second fraction by $\frac{2}{2}$

$\frac{3*3}{2*3}$ a - $\frac{4*3}{3*3}$ a = $\frac{10+8a}{3}$

4. Solve by making a the subject

$\frac{9a-8a}{6}$ = $\frac{10+8a}{3}$

$\frac{a}{6}$ = $\frac{10+8a}{3}$

$\frac{3a}{6}$ =10+8a

$\frac{a}{2}$ = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = $\frac{20}{-15}$

a = $\frac{4}{-3}$

Therefore, the answer is a = $\frac{4}{-3}$

Keyword: Equations

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