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lawyer [7]
3 years ago
13

How much more pizza is in a 12-in.diameter pizza than an 8-in.diameter pizza?

Mathematics
2 answers:
lyudmila [28]3 years ago
4 0

Answer: 62.8 in2

Step-by-step explanation:

e-lub [12.9K]3 years ago
3 0

Answer:

62.8 in2

Step-by-step explanation:

With round pizza we need to

find the area of each pizza in

square inches, then determine

the difference.  

The area of a circle is given by:

A = πr2

 

12 inch diameter, radius = 6

a = π(62) = 36π in2

 

8 inch diameter, radius = 4

a = π(42) = 16π in2

 

Difference:  36π - 16π = 20π in2

 

using 3.14 for pi, the difference is

20(3.14) = 62.8 in2

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sergey [27]
Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval
6 0
2 years ago
P(A)=7/20,P(B)=3/5,P(A∩B)=21/100 ,P(A∪B)=?
satela [25.4K]

Answer:

P( A U B) = 37/50

Step-by-step explanation:

7/20+3/5+21/100

IF YOU NEED MORE HELP LMK

7 0
3 years ago
Read 2 more answers
Perform the indicated operation. 4/11 x 10/8
Mrrafil [7]
 5/11 because if you simplify starting at 40/88 you get 5/11
5 0
3 years ago
Read 2 more answers
UJUU J
Stels [109]

Answer:

Plese read the complete procedure below:

Step-by-step explanation:

The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)

a)

1   -6   3   26   -24    |<u>  1     </u>

<u>      1   -5   -2    24</u>

1   -5   -2   24    0

The remainder is zero, then (a-1) is a factor of the polynomial

b)

1   -6   3   26   -24    |<u>  2     </u>

<u>      2  -8   10    72</u>

1   -4   5   36    48

When p(a) is divided by (a-2) the remainder 28/p(a)

1   -6   3   26   -24    |<u> - 4     </u>

<u>    -4  40  172  -792</u>

1   -10  43  198  -816

When p(a) is divided by (a-2) the remainder -816/p(a)

c) I attached an image of the long division below:

3 0
3 years ago
Given:
lys-0071 [83]

Answer:

PS=13\text{ units}

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

(PQ)^2+(QR)^2=(PR)^2

We know that PR is 20.

QR is the combined length of QS+SR, so QR is 5+11 or 16.

So, substitute:

(PQ)^2+(16)^2=(20)^2

Solve for PQ. Square:

(PQ)^2+256=400

Subtract 256 from both sides:

(PQ)^2=144

Take the square root of both sides:

PQ=12

So, the side length of PQ is 12.

Now, we can use the Pythagorean Theorem again to find PS. Notice that PQ, QS, and PS also form a right triangle, with PS being the hypotenuse. So:

(PQ)^2+(QS)^2=(PS)^2

We already know that QS is 5. We also just determined that PQ is 12. Substitute:

(12)^2+(5)^2=(PS)^2

Square:

144+25=(PS)^2

Add:

169=(PS)^2

Take the square root of both sides:

PS=13

Therefore, the length of PS is 13 units.

And we're done!

7 0
3 years ago
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