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Ratling [72]
3 years ago
11

Grissom draws different sized spheres in a notebook. He knows there is a relationship between the volume of the sphere and the l

ength of its diameter. What is the independent quantity in the situation?
Mathematics
1 answer:
grigory [225]3 years ago
4 0

Answer:

The independent quantity in the situation is the length of the diameter.

Step-by-step explanation:

Consider a relationship between two variables.

Of the two variables one variable is dependent upon the other.

Dependent variables are those variables that are under study, i.e. they are being observed for any changes when the other variable values are changed.

Independent variables are the variables that are being altered to see a proportionate change in the dependent variable.

In this case, it is provided that Grissom knows there is a relationship between the volume of the sphere and the length of its diameter.

With every sphere that Grissom draws, the volume of the sphere changes according to its diameter length.

That is the volume of the sphere depends upon the length of its diameter.

Thus, the independent quantity in the situation is the length of the diameter.

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PLEASE HELP ME BOTH MY TUTORS LEFT AT THE SAME TIME I NEED MAJOR HELP!!! PPPPLLLLEEEEAAAASSSSEEE
Elenna [48]
Problem 1

The formula to use is
s = r*theta

where,
s = arc length
r = radius
theta = angle in radians
Note: if the angle is not in radians, you have to convert it over to radians. However, in this case we are told the angle is "5pi/4 radians". So no conversion is needed.

In this case,
s = unknown (this is what we want to solve for)
r = 34
theta = 5pi/4
keep in mind that 5pi/4 is the same as (5/4)*pi

----------------------------

Plug the value of r and theta into the formula to get...
s = r*theta
s = 34*(5pi/4)
s = (34*5/4)*pi
s = 42.5*pi
s = 42.5*3.14
s = 133.45

----------------------------
----------------------------

Final Answer: 133.45

===============================================

Problem 2

sin(angle) = opposite/hypotenuse
sin(61.7) = 8/y
y*sin(61.7) = 8
y = 8/sin(61.7)
y = 9.08598042654456 ... use a calculator
y = 9 ... rounding to the nearest whole number

----------------------------
----------------------------

Final Answer: 9

===============================================

Problem 3

We need to know the length of BC. Let's call this x for now. Use the pythagorean theorem to find x

x^2 + 14^2 = 50^2
x^2 + 196 = 2500
x^2 + 196-196 = 2500-196
x^2 = 2304
sqrt(x^2) = sqrt(2304)
x = 48

So BC = 48 units long
Now we can compute the tangent of angle B

----------------------------

tan(angle) = opposite/adjacent
tan(B) = AC/BC
tan(B) = 14/48
tan(B) = 7/24

----------------------------
----------------------------

Final Answer: 7/24

===============================================

Problem 4

In this current stage, I cannot answer this question because the image isn't showing up. On my end, all I see is a black rectangle with no triangle showing. It seems like some kind of glitch is happening. Please repost this image. Thank you.

===============================================

Problem 5

There are multiple answers here so it seems like there should be a restriction. Does it state what the restriction must be? Please let me know. Thank you. 

===============================================

Problem 6

Rule:
sin(x) = cos(90-x)
where x is an angle in degrees

----------------------------

Using that rule mentioned above, we can replace the "sin(x)" term with "cos(90-x)" then solve for x

cos(63) = sin(x)
cos(63) = cos(90-x)
both arguments must be equal, so 63 must be equal to 90-x

63 = 90-x
63+x = 90-x+x
x+63 = 90
x+63-63 = 90-63
x = 27

----------------------------
----------------------------

Final Answer: 27
5 0
3 years ago
(03.01 lc) the leg of a right triangle is 2 units and the hypotenuse is 3 units. What is the length, in units of the other leg o
zheka24 [161]
Hypotenuse^2 = leg1^2 + leg2^2
3^2 = 2^2 + leg2^2
leg2^2 = 3^2 -2^2
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3 years ago
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You need to specify whether this situation involves compounding, and, if it does, whether it's continuous compounding, monthly, annual or what.

Just supposing that it's semi-annual compounding:


A = $35000 (1 + 0.051/2)^(5*2)

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aksik [14]

Answer:

  • See below

Step-by-step explanation:

1. JK ∥ LM, KL ∥ MN                                 Given

2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL           c. Corresponding Angles  

3. JK ≅ LM                                               Given

4. ∆JKL ≅ ∆LMN                                     e. AAS

5 0
2 years ago
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