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3 years ago

Should i add, multiply, subtract, or divide n+16=9

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

Subtract 16 to 9 and youll get n

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Given h(x) = 2x - 3 , solve for when h(x) = - 3 .

FrozenT [24]

Answer:

h(x)=-3;x=0

Step-by-step explanation:

When given h(x), you are in effect, being given the output of the function.

So, placing h(x)=-3 in place for h(x)

We get

-3=2x-3

Where -3+3=2x

0=2x

x=0

So, x=0

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3 years ago

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Alex73 [517]

Answer:

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Step-by-step explanation:

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4 years ago

Square root of 69x420

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3 years ago

T U S If T is the midpoint of SU, what are ST, TU, and SU? . 9x 6x + 30

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4 years ago

Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.)

Luda [366]

Answer:

$a.b = (1*0) + (-4*2) +(1*-2)= -10$

And replacing we got:

$cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}$

And we can find the angle with the inverse cosine function and we got:

$\theta =cos^{-1} (-\frac{5}{6})= 146.44°$

Step-by-step explanation:

for this case we can use the following identity:

$cos \theta = \frac{a.b}{|a| |b|}$

We can begin finding the norm for each vector and we got:

$|a| =\sqrt{(1)^2 +(-4)^2 +(1)^2}= \sqrt{18}$

$|b| =\sqrt{(0)^2 +(2)^2 +(-2)^2}= \sqrt{8}$

Now we can find the dot product and we got:

$a.b = (1*0) + (-4*2) +(1*-2)= -10$

And replacing we got:

$cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}$

And we can find the angle with the inverse cosine function and we got:

$\theta =cos^{-1} (-\frac{5}{6})= 146.44°$

5 0

3 years ago