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Leokris [45]
3 years ago
8

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b

elow is equal to the measure of the exterior angle.
Step 1: m∠m + m∠n + m∠o = 180 degrees (sum of angles of a triangle)
Step 2: m∠p − m∠o = 90 degrees (alternate interior angles)
Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p
Step 4: So, m∠m + m∠n = m∠p

In which step did the student first make a mistake and how can it be corrected?
Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (corresponding angles)
Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (adjacent angles)
Step 2; it should be m∠o + m∠p = 180 degrees (alternate exterior angles)
Step 2; it should be m∠o + m∠p = 180 degrees (supplementary angles)
Mathematics
1 answer:
iragen [17]3 years ago
7 0

The student made the mistake in Step 2.

It should be m∠o + m∠p = 180 (Supplementary angles)

If this is corrected, then, since m∠m + m∠n + m∠o = 180 from Step 1,

we have,

m∠m + m∠n + m∠o = m∠o + m∠p which is Step 3.

Cancelling m∠o both sides, we get,

m∠m + m∠n = m∠p which is Step 4.

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P = (5, -pi%2F6%2B2n%2Api )

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(-5, -pi%2F6%2B%282n%2B1%29pi)

answer is: (5,-pi%2F6+%2B+2n%2Api) or (-5, -pi%2F6%2B%282n%2B1%29pi)

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A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
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Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

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Surface area of box=2b^2+4bh

2b^2+4bh=36

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\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

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b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

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Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

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h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

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3 years ago
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