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Masja [62]
3 years ago
11

All 6 sides of a cube measure 65mm. Calculate the volume of the cube in cm32

Chemistry
1 answer:
zmey [24]3 years ago
8 0
Same I need help also
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Calculate the atomic mass of gallium, symbol Ga. Gallium has two isotopes: Ga-69 and Ga-71. The relative abundance of Ga-69 is 6
amm1812

Answer:

The atomic mass of gallium (Ga) = <u>69.723 g/mol</u>

Explanation:

Given: Two isotopes of Gallium (Ga) are Gallium-69 (⁶⁹Ga) and Gallium-71 (⁷¹Ga)

<u>For ⁶⁹Ga: </u>

Relative abundance = 60.12% = 60.12 ÷ 100 = 0.6012; Atomic mass = 68.9257 g/mol

<u>For ⁷¹Ga:</u>

Relative abundance = 39.88% = 39.88 ÷ 100 = 0.3988; Atomic mass = 70.9249 g/mol

∴ The atomic mass of Ga = (Relative abundance of ⁶⁹Ga × Atomic mass of ⁶⁹Ga) + (Relative abundance of ⁷¹Ga × Atomic mass of ⁷¹Ga)

⇒ Atomic mass of Ga = (0.6012 × 68.9257 g/mol) + (0.3988 × 70.9249 g/mol) = <u>69.723 g/mol</u>

<u>Therefore, the atomic mass of gallium (Ga) = 69.723 g/mol</u>

8 0
3 years ago
Help PlS AFAP and thank you so much
Triss [41]

Answer:

B

Explanation:

idk how to explain, B is the definition of conduction

8 0
3 years ago
Read 2 more answers
Help pls!!!!!!!!!!!!!​
UkoKoshka [18]

Answer:

1.   C + O₂ → CO₂

2.  C + CO₂ → 2 CO

3. Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

4 0
2 years ago
PLEASE HELP ME I NEED HELP. DO NOT GIVE ANY WRONG ANSWERS.
Lemur [1.5K]
I believe the answer is C
3 0
3 years ago
a student prepares a dilute solution of sodium hydroxidem, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.
Serjik [45]

Answer:

M = 0.3077 M

Explanation:

As I said in the comments, you are missing the required volume of the base to react with the KHP. I found this on another site, and the volume it used was 21.84 mL.

Now, KHP is a compound often used to standarize NaOH or KOH solutions. This is because it contains a mole ratio of 1:1 with the base, so it's pretty easy to use and standarize any base.

Now, as we are using an acid base titration, the general expression to use when a acid base titration reach the equivalence point would be:

n₁ = n₂   (1)

This, of course, if the mole ratio is 1:1. In the case of KHP and NaOH it is.

Now, we also know that moles can be expressed like this:

n = M * V   (2)

And according to this, we are given the volume of base and the required mass of KHP. So, if we want to know the concentration of the base, we need to get the moles of the KHP, because in the equivalence point, these moles are the same moles of base.

The reported molar mass of KHP is 204.22 g/mol, so the moles are:

n = 1.372 / 204.22 = 6.72x10⁻³ moles

Now, we will use expression (2) to get the concentration of the diluted base:

n = M * V

M = n / V

M = 6.72x10⁻³ / 0.02184

M NaOH = 0.3077 M

This is the concentration of the dilute solution of NaOH

3 0
3 years ago
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