8/5lit.. of 12M NaOH
2/5lit.. of 2M NaOH
Answer:
1.Hydrogenation of Alkenes and akynes.
2.Reaction of alkylhalides.
3. Halogenation.
Answer:
MECHANISM:
1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.
2) Formation of carbocation.
3) Attack of Nucleophile Br − .
Explanation:
If sodium is burned in chlorine fuel, a compound is formed that dissolves in water. the solution be: Bright yellow mild
Chlorine is a yellow-green gas at room temperature. Chlorine has a smelly, annoying scent similar to bleach that is detectable at low concentrations. The density of chlorine gasoline is about 2.5 times extra than air, so one can reason it to initially stay near the floor in regions with little air movement.
Chlorine gasoline can be recognized by using its smelly, anxious smell, which is like the scent of bleach. The sturdy scent may additionally provide a good enough caution to human beings that they have been uncovered. Chlorine fuel appears to be yellow-green in color. Concentrations of approximately 400 ppm and past are commonly fatal over a half-hour, and at 1,000 ppm and above, fatality ensues within only some mins. A spectrum of scientific findings can be present in those uncovered to excessive tiers of chlorine.
Learn more about Chlorine here:
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Answer:
a. Kp=1.4


b.Kp=2.0 * 10^-4


c.Kp=2.0 * 10^5


Explanation:
For the reaction
A(g)⇌2B(g)
Kp is defined as:

The conditions in the system are:
A B
initial 0 1 atm
equilibrium x 1atm-2x
At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.
Replacing these values in the expression for Kp we get:

Working with this equation:

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1
The general expression to solve these kinds of equations is:
(equation 1)
We just take the positive values from the solution since negative partial pressures don´t make physical sense.
Kp = 1.4


With x1 we get a partial pressure of:


Since negative partial pressure don´t make physical sense x1 is not the solution for the system.
With x2 we get:


These partial pressures make sense so x2 is the solution for the equation.
We follow the same analysis for the other values of Kp.
Kp=2*10^-4
X1=0.505
X2=0.495
With x1


Not sense.
With x2


X2 is the solution for this equation.
Kp=2*10^5
X1=50001

With x1


Not sense.
With x2


X2 is the solution for this equation.