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Margaret [11]
2 years ago
14

Ernesto brought plastic tubes that are each 5.3 meters long. If Ernesto makes a line of 18 tubes by placing the end-to-end, how

long will it be?
Mathematics
1 answer:
VARVARA [1.3K]2 years ago
3 0

5.3×18=95.4 meters. you multiply it because you are trying to find the full length.

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The side length of an equilateral triangle is 5 cm.<br><br> Find its perimeter
ollegr [7]
Answer: 15 cm

Step-by-Step Explanation:

Side Length (a) = 5cm
Perimeter = 3a

Therefore,
= 3a
= 3 * 5
= 15

Perimeter = 15 cm
8 0
1 year ago
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Use the distributive property to simplify the expressions. 1B. -3(9x-q) 2B. 2(12+5p) 3b. -7(-8y+7) 4b. 10(2+7c) 5b. -8(7+11k) 6b
Debora [2.8K]
1B: -3(9x-q)
       -27x + 3q


Step 1: Distribute the -3 to the 9x to get -27x.
Step 2: Distribute the -3 to the -q.


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       24 + 10p

Step 1: Distribute the 2 to the 12 to get 24.
Step 2: Distribute the 2 to the 5p to get 10p.

3B: -7(-8y+7)
       56y - 49


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Step 2: Distribute the -7 to the 7 to get -49.

4B: 10(2+7c)
        20 + 70c


Step 1: Distribute the 10 to the 2 to get 20. 
Step 2: Distribute the 10 to the 7c to get 70c.

5B: -8(7+11k)
       -56 - 88k


Step 1: Distribute the -8 to the 7 to get -56.
Step 2: Distribute the -8 to the 11k to get -88k.

6B: -(3-7u)
       -1(3-7u)
       -3 + 7u


Step 1: Place a 1 after the negative symbol to symbolize -1.
Step 2: Distribute the -1 to the three to get -3.
Step 3: Distribute the -1 to the -7u to get 7u.


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Step 1: Distribute the -6 to the 5p to get -30p.
Step 2: Distribute the -6 to the s to get -6s.

:) :D




8 0
3 years ago
Say you're playing three-card poker; that is, you're dealt three cards in a row at random from a standard deck of 52 cards. What
Brums [2.3K]

Answer:

Step-by-step explanation:

Given

There are 52 cards in total

there are total of 13 pairs of same cards with each pair containing 4 cards

Probability of getting a pair or three of kind card=1-Probability of all three cards being different

Probability of selecting all three different cards can be find out by selecting a card from first 13 pairs and remaining 2 cards from remaining 12 pairs i.e.

=\frac{52\times 48\times 44}{52\times 51\times 50}

for first card there are 52 options after choosing first card one pair is destroyed as we have to select different card .

For second card we have to select from remaining 12 pairs i.e. 48 cards and so on for third card.

Required Probability is =1-\frac{52\times 48\times 44}{52\times 51\times 50}

=\frac{22776}{132600}

7 0
2 years ago
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pentagon [3]
The answer is 5 1/2.
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Lady_Fox [76]

Answer:

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Step-by-step explanation:

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0.22

7 0
3 years ago
Read 2 more answers
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